g.:
String string="Marc Louie, Garduque Bautista";
I want to check if a string contains only words, a comma and spaces. i have tried to use regex and the closest I got is this :
String pattern = "[a-zA-Z]+(\\s[a-zA-Z]+)+";
but it doesnt check if there is a comma in there or not. Any suggestion ?
To validate a string for alphabets you can either compare each character in the String with the characters in the English alphabet (both cases) or, use regular expressions.
You can use the Pattern. matches() method to quickly check if a text (String) matches a given regular expression. Or you can compile a Pattern instance using Pattern. compile() which can be used multiple times to match the regular expression against multiple texts.
You need to use the pattern
^[A-Za-z, ]++$
For example
public static void main(String[] args) throws IOException {
final String input = "Marc Louie, Garduque Bautista";
final Pattern pattern = Pattern.compile("^[A-Za-z, ]++$");
if (!pattern.matcher(input).matches()) {
throw new IllegalArgumentException("Invalid String");
}
}
EDIT
As per Michael's astute comment the OP might mean a single comma, in which case
^[A-Za-z ]++,[A-Za-z ]++$
Ought to work.
Why not just simply:
"[a-zA-Z\\s,]+"
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