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In Java, I am trying to split on the ^ character, but it is failing to recognize it. Escaping \^ throws code error.
Is this a special character or do I need to do something else to get it to recognize it?
String splitChr = "^"; String[] fmgStrng = aryToSplit.split(splitChr); 
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To split a string by special characters, call the split() method on the string, passing it a regular expression that matches any of the special characters as a parameter. The method will split the string on each occurrence of a special character and return an array containing the results. Copied!
backslash-dot is invalid because Java doesn't need to escape the dot. You've got to escape the escape character to get it as far as the regex which is used to split the string.
The split() method divides the string at the specified regex and returns an array of substrings.
The ^ is a special character in Java regex - it means "match the beginning" of an input.
You will need to escape it with "\\^". The double slash is needed to escape the \, otherwise Java's compiler will think you're attempting to use a special \^ sequence in a string, similar to \n for newlines.
\^ is not a special escape sequence though, so you will get compiler errors.
In short, use "\\^".
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