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How do you generate a secure random (or pseudo-random) alphanumeric string in Java efficiently?
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SecureRandom randomGenerator = new SecureRandom(); byte[] randomBytes = new byte[20]; randomGenerator. nextBytes(randomBytes); String randomString = new BigInteger(1, randomBytes). toString(16); It you want to a little more efficient variant, specify randomGenerator as class field or as a static field.
Generating a Secure Random String$random = random_bytes(10); The function returns a random string, suitable for cryptographic use, of the number bytes passed as an argument (10 in the above example). The random_bytes() function returns a binary string which may contain the \0 character.
Using randomUUID() java. util. UUID is another Java class that can be used to generate a random string. It offers a static randomUUID() method that returns a random alphanumeric string of 32 characters.
Initialize an array containing all the accepted chars (CHARS_ARRAY), then instantiate a SecureRandom instance, and call nextInt(CHARS_ARRAY.length) repeatedly to get a random index in your char array. Append each char to a StringBuilder until you get the expected number of chars.
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