Java optional parameters

Question

What specification supports optional parameters?

Answer 1

There are several ways to simulate optional parameters in Java:

1. Method overloading.

   void foo(String a, Integer b) { //... }

   void foo(String a) { foo(a, 0); // here, 0 is a default value for b }

   foo("a", 2); foo("a");

One of the limitations of this approach is that it doesn't work if you have two optional parameters of the same type and any of them can be omitted.

1. Varargs.

a) All optional parameters are of the same type:

    void foo(String a, Integer... b) {         Integer b1 = b.length > 0 ? b[0] : 0;         Integer b2 = b.length > 1 ? b[1] : 0;         //...     }      foo("a");     foo("a", 1, 2); 

b) Types of optional parameters may be different:

    void foo(String a, Object... b) {         Integer b1 = 0;         String b2 = "";         if (b.length > 0) {           if (!(b[0] instanceof Integer)) {                throw new IllegalArgumentException("...");           }           b1 = (Integer)b[0];         }         if (b.length > 1) {             if (!(b[1] instanceof String)) {                  throw new IllegalArgumentException("...");             }             b2 = (String)b[1];             //...         }         //...     }      foo("a");     foo("a", 1);     foo("a", 1, "b2"); 

The main drawback of this approach is that if optional parameters are of different types you lose static type checking. Furthermore, if each parameter has the different meaning you need some way to distinguish them.

1. Nulls. To address the limitations of the previous approaches you can allow null values and then analyze each parameter in a method body:

   void foo(String a, Integer b, Integer c) { b = b != null ? b : 0; c = c != null ? c : 0; //... }

   foo("a", null, 2);

Now all arguments values must be provided, but the default ones may be null.

1. Optional class. This approach is similar to nulls, but uses Java 8 Optional class for parameters that have a default value:

   void foo(String a, Optional bOpt) { Integer b = bOpt.isPresent() ? bOpt.get() : 0; //... }

   foo("a", Optional.of(2)); foo("a", Optional.absent());

   Optional makes a method contract explicit for a caller, however, one may find such signature too verbose.

   Update: Java 8 includes the class java.util.Optional out-of-the-box, so there is no need to use guava for this particular reason in Java 8. The method name is a bit different though.

2. Builder pattern. The builder pattern is used for constructors and is implemented by introducing a separate Builder class:

   class Foo {     private final String a;      private final Integer b;      Foo(String a, Integer b) {       this.a = a;       this.b = b;     }      //... }  class FooBuilder {   private String a = "";    private Integer b = 0;    FooBuilder setA(String a) {     this.a = a;     return this;   }    FooBuilder setB(Integer b) {     this.b = b;     return this;   }    Foo build() {     return new Foo(a, b);   } }  Foo foo = new FooBuilder().setA("a").build(); 

3. Maps. When the number of parameters is too large and for most of the default values are usually used, you can pass method arguments as a map of their names/values:

   void foo(Map<String, Object> parameters) { String a = ""; Integer b = 0; if (parameters.containsKey("a")) { if (!(parameters.get("a") instanceof Integer)) { throw new IllegalArgumentException("..."); } a = (Integer)parameters.get("a"); } if (parameters.containsKey("b")) { //... } //... }

   foo(ImmutableMap.<String, Object>of( "a", "a", "b", 2, "d", "value"));

   In Java 9, this approach became easier:

   @SuppressWarnings("unchecked") static <T> T getParm(Map<String, Object> map, String key, T defaultValue) {   return (map.containsKey(key)) ? (T) map.get(key) : defaultValue; }  void foo(Map<String, Object> parameters) {   String a = getParm(parameters, "a", "");   int b = getParm(parameters, "b", 0);   // d = ... }  foo(Map.of("a","a",  "b",2,  "d","value")); 

Please note that you can combine any of these approaches to achieve a desirable result.

Answer 2

varargs could do that (in a way). Other than that, all variables in the declaration of the method must be supplied. If you want a variable to be optional, you can overload the method using a signature which doesn't require the parameter.

private boolean defaultOptionalFlagValue = true;  public void doSomething(boolean optionalFlag) {     ... }  public void doSomething() {     doSomething(defaultOptionalFlagValue); }