From what I understand the & operator is similar to the && operator except that the && only checks the second if the first is true, while the & checks both regardless of the result of the first one. Basically the && just saves a little time and power.
If that is so, then how does this code work?
int l = 0;
if ((l & 8) != 0 && (l & 4) == 0){ do something}
what does the (l & 8)
and the (l & 4)
do?
What does the & do in this case?
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& and && are two different operators but the difference is not what you've described.
& does the bit-wise AND of two integers and produces a third integer whose bit are set to 1 if both corresponding bits in the two source integers are both set to 1; 0 otherwise.
&& applies only to two booleans and returns a third boolean which will be true if both the input booleans are true; false otherwise.
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