Java new byte array of size 2^32

Question

In Java, it won't allow me to use a long for something like this:

long size = 0xFFFFFFFF; //2^32-1

byte [] data = new byte[size];

And an int can only go as high as 0x7FFFFFFF (2^31-1). Is it possible to declare a byte array of this size?

Answer 1

Answer is NO as this is the max possible initialization:

    int size = Integer.MAX_VALUE;
    byte [] data = new byte[size];

Answer 2

Declare the size as an int and try again:

int size = 0x7FFFFFFF; // 0x7FFFFFFF == Integer.MAX_vALUE == 2^32-1

An array can only be declared to have a positive int size, not a long. And notice that the maximum int positive value (and hence, the maximum possible size for an integer array, assuming there's enough memory available) is 0x7FFFFFFF == Integer.MAX_vALUE.