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To obtain the character "%" in a format string, enter "%%", e.g. printf("The percentage is %d %%. *n",5); yields The percentage is 5 %.
The % symbol has a special use in a printf statement. How would you place this character as part of the output on the screen? You can do this by using %% in the printf statement. For example, you can write printf(“10%%”) to have the output appear as 10% on the screen.
The percent sign is escaped using a percent sign: System. out. printf("%s\t%s\t%1.2f%%\t%1.2f%%\n",ID,pattern,support,confidence);
The percent sign is escaped using a percent sign:
System.out.printf("%s\t%s\t%1.2f%%\t%1.2f%%\n",ID,pattern,support,confidence);
The complete syntax can be accessed in java docs. This particular information is in the section Conversions of the first link.
The reason the compiler is generating an error is that only a limited amount of characters may follow a backslash. % is not a valid character.
Escaped percent sign is double percent (%%):
System.out.printf("2 out of 10 is %d%%", 20);
You can use StringEscapeUtils from Apache Commons Logging utility or escape manually using code for each character.
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