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I have a uint8 (unsigned 8 bit integer) coming in from a UDP packet. Java only uses signed primitives. How do I parse this data structure correctly with java?
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Constructs a new 8-bit unsigned parameter. UInt8(IntegerParameter value) Constructs a new instance with the same value as in the passed IntegerParameter . UInt8(short value) Constructs a new 8-bit unsigned parameter.
Convert byte[] to String (text data) toString() to get the string from the bytes; The bytes. toString() only returns the address of the object in memory, NOT converting byte[] to a string ! The correct way to convert byte[] to string is new String(bytes, StandardCharsets. UTF_8) .
Java doesn't have unsigned bytes (0 to 255). To make an unsigned byte, we can cast the byte into an int and mask (bitwise and) the new int with a 0xff to get the last 8 bits or prevent sign extension. byte aByte = -1; int number = aByte & 0xff; // bytes to unsigned byte in an integer.
Byte Array to int and long. Now, let's use the BigInteger class to convert a byte array to an int value: int value = new BigInteger(bytes). intValue();
Simply read it as as a byte and then convert to an int.
byte in = udppacket.getByte(0); // whatever goes here
int uint8 = in & 0xFF;
The bitmask is needed, because otherwise, values with bit 8 set to 1 will be converted to a negative int. Example:
This: 10000000
Will result in: 11111111111111111111111110000000
So when you afterwards apply the bitmask 0xFF to it, the leading 1's are getting cancelled out. For your information: 0xFF == 0b11111111
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0xFF & number will treat the number as unsigned byte. But the resultant type is int
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