Java: How to get the caller function name

Question

To fix a test case I need to identify whether the function is called from a particular caller function. I can't afford to add a boolean parameter because it would break the interfaces defined. How to go about this?

This is what I want to achieve. Here I can't change the parameters of operation() as it is an interface implementation.

operation() {    if not called from performancetest() method        do expensive bookkeeping operation    ...         } 

Answer 1

You could try

StackTraceElement[] stacktrace = Thread.currentThread().getStackTrace(); StackTraceElement e = stacktrace[2];//maybe this number needs to be corrected String methodName = e.getMethodName(); 

Answer 2

Here's a function I wrote to Log the function name of the function that calls it. It runs up the stack trace until it finds a function named logIt, then displays the next name. It's a dirty hack, so don't do it unless you're using it to debug.

private static void logIt() {     StackTraceElement[] stacktrace = Thread.currentThread().getStackTrace();     boolean logged = false;     boolean foundMe = false;     for(int i=0; i<stacktrace.length; i++) {         StackTraceElement e = stacktrace[i];         String methodName = e.getMethodName();         if (foundMe) {             if (!methodName.startsWith("access$")) {                 Log.i(TAG, String.format(Locale.US, "%s.%s", e.getClassName(), methodName));                 logged = true;                 break;             }         } else {             if (methodName.equals("logIt")) {                 foundMe = true;             }         }     }     if (!logged)         Log.e(TAG, "unlogged call"); }