Java HashMap vs JSONObject

Question

I am wondering about the performance of Java HashMap vs JSONObject.

It seems JSONObject stores data internally using HashMap. But JSONObject might have additional overhead compared to HashMap.

Does any one know about the performance of Java JSONObject compared to HashMap?

Thanks!

Answer 1

As you said, JSONObject is backed by a HashMap.

Because of this, performance will be almost identical. JSONObject.get() adds a null check, and will throw an exception if a key isn't found. JSONObject.put() just calls map.put().

So, there is almost no overhead. If you are dealing with JSON objects, you should always use JSONObject over HashMap.

Answer 2

I would say the question doesn't make sense for a few reasons:

1. Comparing apples to oranges: HashMap and JSONObject are intended for 2 completely different purposes. It's like asking "is the Person class or Company class more efficient for storing a PhoneNumber object". Use what makes sense.
2. If you are converting to/from JSON, you are likely sending the data to a far away place (like a user's browser). The time taken to send this data over the network and evaluate it in the user's browser will (likely) far eclipse any performance differences of populating a Hashmap or JSONObject.
3. There is more than 1 "JSONObject" implementation floating around out there.
4. Finally, you haven't asked about what sort of performance you would like to measure. What are you actually planning to do with these classes?

Answer 3

Existing answers are correct, performance differences between the two are negligible.

Both are basically rather inefficient methods of storing and manipulating data. More efficient method is typically to bind into regular Java objects, which use less memory and are faster to access. Many developers use org.json's simple (primitive) library because it is well-known, but it is possible the least convenient and efficient alternative available. Choices like Jackson and Gson are big improvements so it is worth considering using them.