Wildcards in Java are basically the question marks which we use in generic programming, it basically represents the unknown type. We use Java Wildcard widely in situations such as in a type of parameter, local variable, or field and also as a return type.
In generic code, the question mark (?), called the wildcard, represents an unknown type. The wildcard can be used in a variety of situations: as the type of a parameter, field, or local variable; sometimes as a return type (though it is better programming practice to be more specific).
both bounded and unbounded wildcards provide a lot of flexibility on API design especially because Generics is not covariant and List<String> can not be used in place of List<Object>. Bounded wildcards allow you to write methods that can operate on Collection of Type as well as Collection of Type subclasses.
Explanation: In generic code, the question mark (?), called the wildcard, represents an unknown type.
In your first question, <? extends T>
and <? super T>
are examples of bounded wildcards. An unbounded wildcard looks like <?>
, and basically means <? extends Object>
. It loosely means the generic can be any type. A bounded wildcard (<? extends T>
or <? super T>
) places a restriction on the type by saying that it either has to extend a specific type (<? extends T>
is known as an upper bound), or has to be an ancestor of a specific type (<? super T>
is known as a lower bound).
The Java Tutorials have some pretty good explanations of generics in the articles Wildcards and More Fun with Wildcards.
If you have a class hierarchy A, B is a subclass of A, and C and D both are subclass of B like below
class A {}
class B extends A {}
class C extends B {}
class D extends B {}
Then
List<? extends A> la;
la = new ArrayList<B>();
la = new ArrayList<C>();
la = new ArrayList<D>();
List<? super B> lb;
lb = new ArrayList<A>(); //fine
lb = new ArrayList<C>(); //will not compile
public void someMethod(List<? extends B> lb) {
B b = lb.get(0); // is fine
lb.add(new C()); //will not compile as we do not know the type of the list, only that it is bounded above by B
}
public void otherMethod(List<? super B> lb) {
B b = lb.get(0); // will not compile as we do not know whether the list is of type B, it may be a List<A> and only contain instances of A
lb.add(new B()); // is fine, as we know that it will be a super type of A
}
A bounded wildcard is like ? extends B
where B is some type. That is, the type is unknown but a "bound" can be placed on it. In this case, it is bounded by some class, which is a subclass of B.
Josh Bloch also has a good explanation of when to use super
and extends
in this google io video talk where he mentions the Producer extends
Consumer super
mnemonic.
From the presentation slides:
Suppose you want to add bulk methods to
Stack<E>
void pushAll(Collection<? extends E> src);
– src is an E producer
void popAll(Collection<? super E> dst);
– dst is an E consumer
There may be times when you'll want to restrict the kinds of types that are allowed to be passed to a type parameter. For example, a method that operates on numbers might only want to accept instances of Number or its subclasses. This is what bounded type parameters are for.
Collection<? extends MyObject>
means that it can accept all object who have IS- A relationship with MyObject (i.e. any object which is a type of myObject or we can say any object of any subclass of MyObject) or a object of MyObject class.
For example:
class MyObject {}
class YourObject extends MyObject{}
class OurObject extends MyObject{}
Then,
Collection<? extends MyObject> myObject;
will accept only MyObject or children of MyObject(i.e. any object of type OurObject or YourObject or MyObject, but not any object of superclass of MyObject).
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