I'm using following code to create a BigInteger
from hexadecimal string and print in to output.
package javaapplication2;
import java.math.BigInteger;
import javax.xml.bind.DatatypeConverter;
public class JavaApplication2 {
public static void main(String[] args) {
// Number in hexadecimal form
String HexString = "e04fd020ea3a6910a2d808002b30309d";
// Convertation from string to byte array
byte[] ByteArray = toByteArray(HexString);
// Creation of BigInteger from byte array
BigInteger BigNumber = new BigInteger(ByteArray);
// Print result
System.out.print(BigNumber + "\n");
}
public static String toHexString(byte[] array) {
return DatatypeConverter.printHexBinary(array);
}
public static byte[] toByteArray(String s) {
return DatatypeConverter.parseHexBinary(s);
}
}
After execution of this code I'm get a following result:
-42120883064304190395265794005525319523
But I'm expected to see this result:
298161483856634273068108813426242891933
What I'm doing wrong?
You're passing in a byte array where the first byte has a top bit that is set - making it negative. From the constructor documentation:
Translates a byte array containing the two's-complement binary representation of a BigInteger into a BigInteger. The input array is assumed to be in big-endian byte-order: the most significant byte is in the zeroth element.
A two's-complement binary representation with a leading set bit is negative.
To get the result you want, you can do any of:
"00"
so that you'll always get a top byte of 0BigInteger(String, int)
constructor, where the sign is inferred from the presence or absence of "-"
at the start of the string. (Obviously you'd pass in 16 as the base.)BigInteger(int, byte[])
constructor, passing 1 as the signum
valueIf your real context is that you've already got the byte array, and you were only parsing it from a hex string for test purposes, I'd use the third option. If you've genuinely got a hex string as input, I'd use the second option.
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