I have a bunch of objects stored in hashMap<Long,Person>
i need to find the person object with a specific attribute without knowing its ID.
for example the person class:
public person{
long id;
String firstName;
String lastName;
String userName;
String password;
String address;
..
(around 7-10 attributes in total)
}
lets say i want to find the object with username = "mike". Is there any method to find it without actually iterating on the whole hash map like this :
for (Map.Entry<Long,Person> entry : map.entrySet()) {
if(entry.getValue().getUserName().equalsIgnoreCase("mike"));
the answers i found here was pretty old.
If you want speed and are always looking for one specific attribute, your best bet is to create another 'cache' hash-map keyed with that attribute.
The memory taken up will be insignificant for less than a million entries and the hash-map lookup will be much much faster than any other solution.
Alternatively you could put all search attributes into a single map (ie. names, and ids). Prefix the keys with something unique if you're concerned with collisions. Something like:
String ID_PREFIX = "^!^ID^!^";
String USERNAME_PREFIX = "^!^USERNAME^!^";
String FIRSTNAME_PREFIX = "^!^FIRSTNAME^!^";
Map<String,Person> personMap = new HashMap<String,Person>();
//add a person
void addPersonToMap(Person person)
{
personMap.put(ID_PREFIX+person.id, person);
personMap.put(USERNAME_PREFIX+person.username, person);
personMap.put(FIRSTNAME_PREFIX+person.firstname, person);
}
//search person
Person findPersonByID(long id)
{
return personMap.get(ID_PREFIX+id);
}
Person findPersonByUsername(String username)
{
return personMap.get(USERNAME_PREFIX+username);
}
//or a more generic version:
//Person foundPerson = findPersonByAttribute(FIRSTNAME_PREFIX, "mike");
Person findPersonByAttribute(String attr, String attr_value)
{
return personMap.get(attr+attr_value);
}
The above assumes that each attribute is unique amongst all the Persons. This might be true for ID and username, but the question specifies firstname=mike which is unlikely to be unique.
In that case you want to abstract with a list, so it would be more like this:
Map<String,List<Person>> personMap = new HashMap<String,List<Person>>();
//add a person
void addPersonToMap(Person person)
{
insertPersonIntoMap(ID_PREFIX+person.id, person);
insertPersonIntoMap(USERNAME_PREFIX+person.username, person);
insertPersonIntoMap(FIRSTNAME_PREFIX+person.firstname, person);
}
//note that List contains no duplicates, so can be called multiple times for the same person.
void insertPersonIntoMap(String key, Person person)
{
List<Person> personsList = personMap.get(key);
if(personsList==null)
personsList = new ArrayList<Person>();
personsList.add(person);
personMap.put(key,personsList);
}
//we know id is unique, so we can just get the only person in the list
Person findPersonByID(long id)
{
List<Person> personList = personMap.get(ID_PREFIX+id);
if(personList!=null)
return personList.get(0);
return null;
}
//get list of persons with firstname
List<Person> findPersonsByFirstName(String firstname)
{
return personMap.get(FIRSTNAME_PREFIX+firstname);
}
At that point you're really getting into a grab-bag design but still very efficient if you're not expecting millions of entries.
The best performance-wise method I can think of is to have another HashMap
, with the key being the attribute you want to search for, and the value being a list of objects.
For your example this would be HashMap<String, List<Person>>
, with the key being the username. The downside is that you have to maintain two maps.
Note: I've used a List<Person>
as the value because we cannot guarantee that username
is unique among all users. The same applies for any other field.
For example, to add a Person
to this new map you could do:
Map<String, List<Person>> peopleByUsername = new HashMap<>();
// ...
Person p = ...;
peopleByUsername.computeIfAbsent(
p.getUsername(),
k -> new ArrayList<>())
.add(p);
Then, to return all people whose username is i.e. joesmith
:
List<Person> matching = peopleByUsername.get("joesmith");
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