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I have configured jersey (with tomcat server) according to the details described until step 6.3 here: http://www.vogella.com/tutorials/REST/article.html#jerseyprojectsetup
Below is my web.xml file, the only difference is that the path/package name for the jersey.config.server.provider.packages
the instructions has;
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>com.vogella.jersey.first</param-value>
because com.vogella.jersey.first is their package name, while I chose to point mine to my default package (jerseytest)
but this is my web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>jerseytest</display-name>
<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<!-- Register resources and providers under com.vogella.jersey.first package. -->
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>jerseytest</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey REST Service</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
when I run the application on the tomcat server I keep getting:
HTTP Status 404 – Not Found
Type Status Report
Message /jerseytest/Description The origin server did not find a current representation for the target resource or is not willing to disclose that one exists.
Apache Tomcat/8.5.23
and when i point the browser to the end point mentioned in the tutorial :
http://localhost:8080/com.vogella.jersey.first/rest/hello
I get a not found error:
HTTP Status 404 – Not Found
Type Status Report
Message Not FoundDescription The origin server did not find a current representation for the target resource or is not willing to disclose that one exists.
Apache Tomcat/8.5.23
When I point the browser directly to http://localhost:8080/rest/hello
I get:
HTTP Status 404 – Not Found
Type Status Report
Message /rest/helloDescription The origin server did not find a current representation for the target resource or is not willing to disclose that one exists.
Apache Tomcat/8.5.23
My java class is identical to the example in the instructions , except that mine is in the default package :
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
// Plain old Java Object it does not extend as class or implements
// an interface
// The class registers its methods for the HTTP GET request using the @GET annotation.
// Using the @Produces annotation, it defines that it can deliver several MIME types,
// text, XML and HTML.
// The browser requests per default the HTML MIME type.
//Sets the path to base URL + /hello
@Path("/hello")
public class Hello {
// This method is called if TEXT_PLAIN is request
@GET
@Produces(MediaType.TEXT_PLAIN)
public String sayPlainTextHello() {
return "Hello Jersey";
}
// This method is called if XML is request
@GET
@Produces(MediaType.TEXT_XML)
public String sayXMLHello() {
return "<?xml version=\"1.0\"?>" + "<hello> Hello Jersey" + "</hello>";
}
// This method is called if HTML is request
@GET
@Produces(MediaType.TEXT_HTML)
public String sayHtmlHello() {
return "<html> " + "<title>" + "Hello Jersey" + "</title>"
+ "<body><h1>" + "Hello Jersey" + "</body></h1>" + "</html> ";
}
}
277
I struggled with this problem many times.
The solution I am currently using is weather the webapp(or the folder where you kept the views like jsp) is under deployment assembly.
To do so
Right click on the project > Build Path > Configure Build path > Deployment Assembly > Add(right hand side) > Folder > (add your jsp folder. In default case it is src/main/webapp)
188
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