Java 8 Streams - Filter More Than One Condition

Question

Based on some sports results data, I have a Fixture object which has getHome() and getAway() method. I'd like to shorten this method which I've written to only use a single lambda function (instead of creating a new list and two lambdas), is this possible?

    private Collection<FixtureResult> finalResults(Team team) {

    List<FixtureResult>finalResults = new ArrayList<>();

    List<FixtureResult> homeResults = resultList.stream().filter(fixture ->
            fixture.getHome().equals(team))
            .collect(toList());

    List<FixtureResult> awayResults = resultList.stream().filter(fixture ->
            fixture.getAway().equals(team))
            .collect(toList());

    finalResults.addAll(homeResults);
    finalResults.addAll(awayResults);

    return finalResults;
}

Answer 1

Simple enough

resultList.stream()
        .filter(fixture -> fixture.getHome().equals(team) || fixture.getAway().equals(team)))
        .collect(toList());

EDIT: This is on the assumption that order does not matter to you. If your final list needs to have home result and then away, have a look at Elliott Frisch's answer.