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Iterator for boost::variant

Hy there,

I'm trying to adapt an existing code to boost::variant. The idea is to use boost::variant for a heterogeneous vector. The problem is that the rest of the code use iterators to access the elements of the vector. Is there a way to use the boost::variant with iterators?

I've tried

 typedef boost::variant<Foo, Bar> Variant;
 std::vector<Variant> bag;
 std::vector<Variant>::iterator it;
 for(it= bag.begin(); it != bag.end(); ++it){

 cout<<(*it)<<endl;
 }

But it didn't work.

EDIT: Thank you for your help! But in my design, I need to get one element from the list and pass it around other parts of the code (and that can be nasty, as I'm using GSL). The idea of using an iterator is that I can pass the iterator to a function, and the function will operate on the return data from that specific element. I can't see how to do that using for_each. I need to do something similar to that:

for(it=list.begin(); it!=list.end();++it) {
  for(it_2=list.begin(); it_2!=list.end();++it_2) {

     if(it->property() != it_2->property()) {

        result = operate(it,it_2);

       }
    }

}

Thanks!

like image 497
Ivan Avatar asked Feb 26 '23 21:02

Ivan


1 Answers

Well of course there is. Dereferencing the iterators will naturally yield a boost::variant<...> reference or const-reference.

However it does mean that the rest of code should be variant-aware. And notably use the boost::static_visitor to execute operations on the variants.

EDIT:

Easy!

struct Printer: boost::static_visitor<>
{
  template <class T>
  void operator()(T const& t) const { std::cout << t << std::endl; }
};

std::for_each(bag.begin(), bag.end(), boost::apply_visitor(Printer());

Note how writing a visitor automatically yields a predicate for STL algorithms, miam!

Now, for the issue of the return value:

class WithReturn: boost::static_visitor<>
{
public:
  WithReturn(int& result): mResult(result) {}

  void operator()(Foo const& f) const { mResult += f.suprise(); }
  void operator()(Bar const& b) const { mResult += b.another(); }

private:
  int& mResult;
};


int result;
std::for_each(bag.begin(), bag.end(), boost::apply_visitor(WithReturn(result)));

EDIT 2:

It's easy, but indeed need a bit of coaching :)

First, we remark there are 2 different operations: != and operate

 struct PropertyCompare: boost::static_visitor<bool>
 {
   template <class T, class U>
   bool operator()(T const& lhs, U const& rhs)
   {
     return lhs.property() == rhs.property();
   }
 };

 struct Operate: boost::static_visitor<result_type>
 {
   result_type operator()(Foo const& lhs, Foo const& rhs);
   result_type operator()(Foo const& lhs, Bar const& rhs);
   result_type operator()(Bar const& lhs, Bar const& rhs);
   result_type operator()(Bar const& lhs, Foo const& rhs);
 };

for(it=list.begin(); it!=list.end();++it) {
  for(it_2=list.begin(); it_2!=list.end();++it_2) {

    if( !boost::apply_visitor(PropertyCompare(), *it, *it_2) ) {

      result = boost::apply_visitor(Operate(), *it, *it_2));

    }

  }
}

For each is not that good here, because of this if. It would work if you could somehow factor the if in operate though.

Also note that I pass not iterators but references.

like image 121
Matthieu M. Avatar answered Mar 07 '23 08:03

Matthieu M.