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iterate through each point on a line/path in java

I'm new to using iterators and was wondering how one would iterate through each point on a line segment (Line2D.Double, to be precise) -- I need to check to see if each point on the line fulfills certain requirements.

Also, given a path object (like GeneralPath), how would you do the same thing (iterate through each point on the outline of the shape)?

Ideally I'd like something like this (with either a line or a path):

Line2D line = new Line2D.Double(p1,p2);
for (Point2D point : line)
{
   point.callSomeMethod();
}
like image 818
scaevity Avatar asked Jan 19 '23 12:01

scaevity


2 Answers

There seems to be nothing in the Java API that makes Bresenham's algorithm user-visible. So I wrote a class that iterates over a line.

You can use it like this:

List<Point2D> points = new ArrayList<Point2D>();
Line2D line = new Line2D.Double(0, 0, 8, 4);
Point2D current;

for (Iterator<Point2D> it = new LineIterator(line); it.hasNext();) {
    current = it.next();
    points.add(current);
}

assertThat(points.toString(), 
    is("[Point2D.Double[0.0, 0.0], Point2D.Double[1.0, 0.0], " +
        "Point2D.Double[2.0, 1.0], Point2D.Double[3.0, 1.0], " +
        "Point2D.Double[4.0, 2.0], Point2D.Double[5.0, 2.0], " +
        "Point2D.Double[6.0, 3.0], Point2D.Double[7.0, 3.0], " +
        "Point2D.Double[8.0, 4.0]]"));
like image 143
nes1983 Avatar answered Jan 23 '23 02:01

nes1983


This will be slow because it will generate a new object for each point. If you need a faster solution, you might want to look into implementing the loop yourself, using the Bresenham algorithm.

like image 42
Thomas Mueller Avatar answered Jan 23 '23 02:01

Thomas Mueller