Is there way of copying the whole array into another array? (Other than using a For-loop)

Question

Is there way of copying the whole array into another array? Other than using a for-loop.

Does the move or copy command work for this? I did try but it had an error: "Incompatible types".

Should I stick to the for-loop?

Answer 1

1- If your array doesn't contain any string or dynamic array, you can use move, but dynamic arrays are not to be handled like fixed-sized arrays:

var A,B: array[0..10] of integer;
    DA, DB: array of double;
    i: integer;
begin
  for i := low(A) to high(A) do
    A[i] := i;
  move(A[0],B[0],length(A)*sizeof(A[0]));  // first version, compiler does the stuff
  move(A[0],B[0],sizeof(A)); // it works
  move(A[0],B[0],40); // if you know what you're doing, since sizeof(A)=40
  SetLength(DA,10); // DA[0]..DA[9]
  for i := 0 to high(DA) do // or for i := 0 to 9 if you know what you're doing
    DA[i] := 
  SetLength(DB,length(DA)); 
  if length(DA)<=length(DB) then // if your dynamic array may be void, use this before to avoid GPF
    move(DA[0],DB[0],length(DA)*sizeof(DA[0]));
  if pointer(DA)<>nil then // this will just check that DA[] is not void
    move(pointer(DA)^,pointer(DB)^,length(DA)*sizeof(double)); // similar to previous
end;

2- If your array contains strings or other reference content array, you have to use a loop:

var A,B: array[0..10] of string;
    i: integer;
begin
  for i := 0 to high(A) do
    A[i] := IntToStr(i);
  for i := 0 to high(A) do
    B[i] := A[i]; // this doesn't copy the string content, just add a reference count to every A[], and copy a pointer: it's very fast indeed
end;