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Is there anyway to create null terminated string in Go?
What I'm currently trying is a:="golang\0" but it is showing compilation error:
non-octal character in escape sequence: "
332
To create a null-terminated string, code: String Y delimited by size X'00' delimited by size into N. To concatenate two null-terminated strings, code: String L delimited by x'00' M delimited by x'00' X'00' delimited by size into N.
GO only allows limited operations on string as it is immutable [3] and represented as a byte-slice. Unlike C/C++, string in Go is not null-terminated.
This: buf[0] = '\0'; puts a null terminator right on the start of the string, overriding c (which you just assigned to buf[0] ).
The strcpy() function copies string2, including the ending null character, to the location that is specified by string1.
Spec: String literals:
The text between the quotes forms the value of the literal, with backslash escapes interpreted as they are in rune literals (except that
\'is illegal and\"is legal), with the same restrictions. The three-digit octal (\nnn) and two-digit hexadecimal (\xnn) escapes represent individual bytes of the resulting string; all other escapes represent the (possibly multi-byte) UTF-8 encoding of individual characters.
So \0 is an illegal sequence, you have to use 3 octal digits:
s := "golang\000"
Or use hex code (2 hex digits):
s := "golang\x00"
Or a unicode sequence (4 hex digits):
s := "golang\u0000"
Example:
s := "golang\000"
fmt.Println([]byte(s))
s = "golang\x00"
fmt.Println([]byte(s))
s = "golang\u0000"
fmt.Println([]byte(s))
Output: all end with a 0-code byte (try it on the Go Playground).
[103 111 108 97 110 103 0]
[103 111 108 97 110 103 0]
[103 111 108 97 110 103 0]
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