I'm a newbie to the JavaScript world. As the title mentions, I want to know whether there is any pre-built method in JavaScript to find all possible permutations of a given string.
For example, given the input:
the
Desired output:
the
teh
eht
eth
het
hte
Step 1: Merge [a] and b: [ba, ab] Step 2: Merge [ba, ab] and c: [cba, bca, bac, cab, acb, abc] Step 3: Merge [cba, bca, bac, cab, acb, abc] and d: [dcba, cdba, cbda, cbad, dbca, bdca, bcda, bcad, dbac, bdac, badc, bacd, dcab, cdab, cadb, cabd, dacb, adcb, acdb, acbd, dabc, adbc, abdc, abcd]
We can find the count without finding all permutation. Idea is to find all the characters that is getting repeated, i.e., frequency of all the character. Then, we divide the factorial of the length of string by multiplication of factorial of frequency of characters.
To calculate the number of permutations, take the number of possibilities for each event and then multiply that number by itself X times, where X equals the number of events in the sequence. For example, with four-digit PINs, each digit can range from 0 to 9, giving us 10 possibilities for each digit.
//string permutation
function permutation(start, string) {
//base case
if ( string.length == 1 ) {
return [ start + string ];
} else {
var returnResult = [];
for (var i=0; i < string.length; i++) {
var result = permutation (string[i], string.substr(0, i) + string.substr(i+1));
for (var j=0; j<result.length; j++) {
returnResult.push(start + result[j]);
}
}
return returnResult;
}
}
permutation('','123') will return
["123", "132", "213", "231", "312", "321"]
function permutations(str){
if (str.length === 1) {
return str;
}
var permut = [];
for (var i=0; i<str.length; i++){
var s = str[0];
var _new = permutations(str.slice(1, str.length));
for(var j=0; j<_new.length; j++) {
permut.push(s + _new[j]);
}
str = str.substr(1, str.length -1) + s;
}
return permut;
}
permutations('the');
//output returns:[ 'the', 'teh', 'het', 'hte', 'eth', 'eht' ]
No pre-built, but writing such function is possible.. here is one relatively simple way using two functions:
function FindAllPermutations(str, index, buffer) {
if (typeof str == "string")
str = str.split("");
if (typeof index == "undefined")
index = 0;
if (typeof buffer == "undefined")
buffer = [];
if (index >= str.length)
return buffer;
for (var i = index; i < str.length; i++)
buffer.push(ToggleLetters(str, index, i));
return FindAllPermutations(str, index + 1, buffer);
}
function ToggleLetters(str, index1, index2) {
if (index1 != index2) {
var temp = str[index1];
str[index1] = str[index2];
str[index2] = temp;
}
return str.join("");
}
Usage:
var arrAllPermutations = FindAllPermutations("the");
Live test case: http://jsfiddle.net/yahavbr/X79vz/1/
This is just basic implementation, it won't remove duplicates and has no optimization. However for small strings you won't have any problem, add time measure like in the above test case and see what's your reasonable limit.
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