For example, I may have one RichText
in current widget tree, that looks like
RichText(
text: TextSpan(
text: 'Hello ',
style: DefaultTextStyle.of(context).style,
children: <TextSpan>[
TextSpan(text: 'bold', style: TextStyle(fontWeight: FontWeight.bold)),
TextSpan(text: ' world!'),
],
),
)
I try to use find.text('Hello bold world!')
but it doesn't work because it's not a Text.
Simplest solution is to put a key on the RichText and read it that way.
If that's not a good fit for whatever reason, you can use find.byWidgetPredicate and pass a function that matches RichText widgets whose text.toPlainText() returns the string you want.
I have recently contributed this feature to the Flutter framework, i.e. to the built-in finders.
find.text()
You can now enable a findRichText
parameter, which will then also find standalone RichText
widgets:
find.text(
'Hello bold world!',
findRichText: true,
)
Here's the find.byWidgetPredicate call.
find.byWidgetPredicate((widget) => fromRichTextToPlainText(widget) == 'Hello bold world!')
Here's the fromRichTextToPlainText helper function. Pass it the RichText widget, it will return the plain text.
String fromRichTextToPlainText(final Widget widget) {
if (widget is RichText) {
if (widget.text is TextSpan) {
final buffer = StringBuffer();
(widget.text as TextSpan).computeToPlainText(buffer);
return buffer.toString();
}
}
return null;
}
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