Is there a way to use super() to call the __init__ method of each base class in Python?

Question

Let's suppose I have a bit of Python code:

class Mother:
    def __init__(self):
        print("Mother")

class Father:
    def __init__(self):
        print("Father")

class Daughter(Mother, Father):
    def __init__(self):
        print("Daughter")
        super().__init__()

d = Daughter()

This script prints "Daughter". Is there anyway to ensure that all of the __init__ methods of the bases classes are called? One method I came up with to do this was:

class Daughter(Mother, Father):
    def __init__(self):
        print("Daughter")
        for base in type(self).__bases__:
            base.__init__(self)

This script prints "Daughter", "Mother", "Father". Is there a nice way to do this using super() or another method?

Answer 1

Raymond Hettinger explained this really well in his talk Super Considered Super from PyCon 2015. The short answer is yes, if you design this way, and call super().__init__() in each class

class Mother:
    def __init__(self):
        super().__init__()
        print("Mother")

class Father:
    def __init__(self):
        super().__init__()
        print("Father")

class Daughter(Mother, Father):
    def __init__(self):
        super().__init__()
        print("Daughter")

The name super is unfortunate, it really works its way through the base classes.