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Is there a way to tell crossfilter to treat elements of array as separate records instead of treating whole array as single key?

I have data set where some of the field values are arrays and I'd like to use crossfilter and d3.js or dc.js to display histogram of how many times each of those values was present in the dataset.

Here's an example:

var data = [     {"key":"KEY-1","tags":["tag1", "tag2"]},     {"key":"KEY-2","tags":["tag2"]},     {"key":"KEY-3","tags":["tag3", "tag1"]}];  var cf = crossfilter(data);  var tags = cf.dimension(function(d){ return d.tags;}); var tagsGroup = tags.group();   dc.rowChart("#chart")     .renderLabel(true)     .dimension(tags)     .group(tagsGroup)     .xAxis().ticks(3);  dc.renderAll(); 

And JSFiddle http://jsfiddle.net/uhXf5/2/

When I run that code it produces graph like this:

graph1

But what I want is something like this:

enter image description here

To make things even more complicated it would be awesome to be able to click on any of the rows and filter dataset by the tag that was clicked.

Anyone has any ideas how to achieve that?

Thanks, Kostya

like image 440
Kostya Marchenko Avatar asked Jul 08 '13 10:07

Kostya Marchenko


2 Answers

Solved it myself, here's fiddle with working code http://jsfiddle.net/uhXf5/6/

Here's code in case someone will came across similar problem:

function reduceAdd(p, v) {   v.tags.forEach (function(val, idx) {      p[val] = (p[val] || 0) + 1; //increment counts   });   return p; }  function reduceRemove(p, v) {   v.tags.forEach (function(val, idx) {      p[val] = (p[val] || 0) - 1; //decrement counts   });   return p;  }  function reduceInitial() {   return {};   }   var data = [     {"key":"KEY-1","tags":["tag1", "tag2"], "date":new Date("10/02/2012")},     {"key":"KEY-2","tags":["tag2"], "date": new Date("10/05/2012")},     {"key":"KEY-3","tags":["tag3", "tag1"], "date":new Date("10/08/2012")}];  var cf = crossfilter(data);  var tags = cf.dimension(function(d){ return d.tags;}); var tagsGroup = tags.groupAll().reduce(reduceAdd, reduceRemove, reduceInitial).value(); // hack to make dc.js charts work tagsGroup.all = function() {   var newObject = [];   for (var key in this) {     if (this.hasOwnProperty(key) && key != "all") {       newObject.push({         key: key,         value: this[key]       });     }   }   return newObject; }   var dates = cf.dimension(function(d){ return d.date;}); var datesGroup = dates.group();   var chart = dc.rowChart("#chart");     chart                                                                                            .renderLabel(true)     .dimension(tags)     .group(tagsGroup)     .filterHandler(function(dimension, filter){              dimension.filter(function(d) {return chart.filter() != null ? d.indexOf(chart.filter()) >= 0 : true;}); // perform filtering         return filter; // return the actual filter value        })     .xAxis().ticks(3);  var chart2 = dc.barChart("#chart2");     chart2       .width(500)     .transitionDuration(800)     .margins({top: 10, right: 50, bottom: 30, left: 40})     .dimension(dates)     .group(datesGroup)     .elasticY(true)     .elasticX(true)     .round(d3.time.day.round)         .x(d3.time.scale())         .xUnits(d3.time.days)     .centerBar(true)     .renderHorizontalGridLines(true)            .brushOn(true);       dc.renderAll(); 
like image 182
Kostya Marchenko Avatar answered Sep 30 '22 18:09

Kostya Marchenko


The example above is a great approach. You can take it one step further though. In the solution above, it will only filter based on the first selection you make. Any subsequent selections are ignored.

If you want it to respond to all selections, you would create a filterHandler as follows:

 barChart.filterHandler (function (dimension, filters) {    dimension.filter(null);        if (filters.length === 0)         dimension.filter(null);     else         dimension.filterFunction(function (d) {             for (var i=0; i < d.length; i++) {                 if (filters.indexOf(d[i]) >= 0) return true;             }             return false;          });   return filters;    } ); 

Working sample here: http://jsfiddle.net/jeffsteinmetz/cwShL/

like image 31
Jeff Steinmetz Avatar answered Sep 30 '22 16:09

Jeff Steinmetz