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In Python 2.6, I want to do:
f = lambda x: if x==2 print x else raise Exception() f(2) #should print "2" f(3) #should throw an exception This clearly isn't the syntax. Is it possible to perform an if in lambda and if so how to do it?
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Just like a normal function, a Lambda function can have multiple arguments with one expression.
Lambda functions does not allow multiple statements, however, we can create two lambda functions and then call the other lambda function as a parameter to the first function.
The syntax you're looking for:
lambda x: True if x % 2 == 0 else False But you can't use print or raise in a lambda.
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