All of the ways I'm seeing involve building structs and unmarshalling the data into the struct. But what if I'm getting JSON responses with hundreds of fields? I don't want to have to create 100 field structs just to be able to get to the data I want. Coming from a Java background there are easy ways to simply get the http response as a string and then pass the JSON string into a JSON object that allows for easy traversal. It's very painless. Is there anything like this in Go?
Java example in pseudo code:
String json = httpResponse.getBody();
JsonObject object = new JsonObject(json);
object.get("desiredKey");
This is a typical scenario we come across. This is achieved by json.Unmarshal
.
Here is a simple json
{"textfield":"I'm a text.","num":1234,"list":[1,2,3]}
which is serialized to send across the network and unmarshaled at Golang end.
package main
import (
"fmt"
"encoding/json"
)
func main() {
// replace this by fetching actual response body
responseBody := `{"textfield":"I'm a text.","num":1234,"list":[1,2,3]}`
var data map[string]interface{}
err := json.Unmarshal([]byte(responseBody), &data)
if err != nil {
panic(err)
}
fmt.Println(data["list"])
fmt.Println(data["textfield"])
}
Hope this was helpful.
The json.Unmarshal method will unmarshal to a struct that does not contain all the fields in the original JSON object. In other words, you can cherry-pick your fields. Here is an example where FirstName and LastName are cherry-picked and MiddleName is ignored from the json string:
package main
import (
"encoding/json"
"fmt"
)
type Person struct {
FirstName string `json:"first_name"`
LastName string `json:"last_name"`
}
func main() {
jsonString := []byte("{\"first_name\": \"John\", \"last_name\": \"Doe\", \"middle_name\": \"Anderson\"}")
var person Person
if err := json.Unmarshal(jsonString, &person); err != nil {
panic(err)
}
fmt.Println(person)
}
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