Is there a way to create a user-defined-literal from `std::initializer_list`?

Question

Just like in the topic: Is there a way to create a user-defined-literal from std::initializer_list?

I am trying to do something like that:

template <typename T> inline
std::initializer_list<T> const & operator "" _lit(std::initializer_list<T> const & list)
{
    return std::move(list); // I am not sure, but this line might cause undefined behavior... well I'll think about it latter...
}

int main()
{
    { 10, 20, 30, 40 }_lit // Error: identifier '_lit' is undefined;

    return 0;
}

But it seems compiler doesn't understand that I am trying to call operator""_lit({10, 20, 30, 40}); Is there any way to fix it?

---

EDIT:
I am sorry, it turns out this is just another example of XY problem ...
Let me elaborate

I am trying to "expand" current C++ syntax (it's a fun little project...)

The main idea is to simplify this:

if ((val_1 == value) && (val_2 == value) && (val_3 == value)) { /* ... */ }

into somehting along the lines:

if (std::initializer_list<T>{val_1, val_2, val_3} == value)

ofc I am providing an additional operator:

template <typename T> inline
bool operator==(std::initializer_list<T> const & list, T const & ref)
{
    for (auto const & element : list)
    {
        if (element == ref) { /* Do nothing. */ }
        else
        {
            return false;
        }
    }
    return true;
}

Everything would be fine and nice, but I dislike the need to type std::initializer_list<T> in front of a curly bracket... Otherwise, the compiler chooses the default version of operator==() and I get a compilation error...

Literals come here as an idea to change if (std::initializer_list<T>{val_1, val_2, val_3} == value) into if ({val_1, val_2, val_3}_lit == value)

Answer 1

template<class T, std::size_t N>
struct any_of:std::array<T, N> {
  #define MAKE_OPERATOR( OPERATOR ) \
    template<class U, \
      std::enable_if_t< std::is_same<void, std::void_t< \
        decltype( std::declval<T const&>() == std::declval<U const&>() ) \
      >>{}, bool> =true \
    > \
    friend bool operator OPERATOR ( any_of const& lhs, U const& rhs) { \
      return std::any_of( \
        lhs.begin(), lhs.end(), \
        [&](auto&& lhs){ return lhs OPERATOR rhs; } \
      ); \
    } \
    template<class U, \
      std::enable_if_t< std::is_same<void, std::void_t< \
        decltype( std::declval<U const&>() == std::declval<T const&>() ) \
      >>{} && !std::is_same< U, any_of >{} , bool> =true \
    > \
    friend bool operator OPERATOR ( U const& lhs, any_of const& rhs) { \
      return std::any_of( \
        rhs.begin(), rhs.end(), \
        [&](auto&& rhs){ return lhs OPERATOR rhs; } \
      ); \
    }
  MAKE_OPERATOR(==)
  MAKE_OPERATOR(!=)
  MAKE_OPERATOR(<)
  MAKE_OPERATOR(<=)
  MAKE_OPERATOR(>=)
  MAKE_OPERATOR(>)
  #undef MAKE_OPERATOR
  explicit any_of( std::array<T, N> arr):std::array<T, N>(std::move(arr)) {}
  template<class...Ts>
  explicit any_of( T t, Ts... ts ):std::array<T, N>{ std::move(t), std::move(ts)... } {}
  any_of( any_of const& )=delete;
  any_of& operator=( any_of const& )=delete;
  any_of()=delete;
};
template<class T, std::size_t N>
any_of(T(&)[N]) -> any_of<T,N>;
template<class T, class...Ts>
any_of(T, Ts...) -> any_of<T, 1+sizeof...(Ts)>;

test code:

if (any_of{1,2,3} == 2) {
    std::cout << "2 is there\n";
}
if (! (any_of{1,2,3} == 7) ){
    std::cout << "7 is not there\n";
}

if (any_of{1,2,3} == any_of{5,6,1}) {
    std::cout << "overlap!\n";
}
if (!(any_of{1,2,3} == any_of{5,6,7})) {
    std::cout << "no overlap!\n";
}

Live example.

Output in c++17 compiler:

2 is there
7 is not there
overlap!
no overlap!

The various comparison operators are all supported.

Cross-type double any_of, like:

any_of{1,2,3} == any_of{3.14, 5.7, 1.0}

will fail to compile because both == of both any_of work.

Answer 2

You can't make a user defined literal for a std::initializer_list. Luckily though C++17 gives a new really cool tool that will help us out. Class template argument deduction allows us to just use the name of a class template, and the compiler will figure out what the template parameters need to be so we don't have to specify them. This means you could leverage std::array and your code would become

template<typename T, std::size_t N>
bool operator==(std::array<T, N> const & list, T const & ref)
{
    for(auto const& e : list)
        if (e != ref)
            return false;
    return true;
}

int main()
{
    using std::array;
    if (array{4,4,4,4,4} == 4)
        std::cout << "all 4";
}

And besides the using statement it is only an extra character between _lit and array