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Is there a nicer way of lifting a PartialFunction in Scala?

I occasionally come across the following pattern, where I essentially have a PartialFunction[SomeType,AnotherType], and want to treat it as a Function[SomeType,Option[AnotherType], eg:

def f(s:SomeType):Option[AnotherType] = s match {
  case s1:SubType1 => Some(AnotherType(s1.whatever))
  case s2:SubType2 => Some(AnotherType(s2.whatever))
  case _ => None
}

Is there a way to write the above function in a way that avoids the default case and wrapping the result in Some where it's defined? The best I've come up with so far is this:

def f(s:SomeType):Option[AnotherType] = pf.lift(s)
def pf:PartialFunction[SomeType,AnotherType] = {
  case s1:SubType1 => AnotherType(s1.whatever)
  case s2:SubType2 => AnotherType(s2.whatever)
}

Is there a way to do it without defining an intermediate function? I've already tried various things along the lines of the following, but haven't got anything to compile yet:

def f:Function[SomeType,Option[AnotherType]] = {
  case s1:SubType1 => AnotherType(s1.whatever)
  case s2:SubType2 => AnotherType(s2.whatever)
}.lift
like image 464
Kristian Domagala Avatar asked Dec 28 '22 02:12

Kristian Domagala


1 Answers

condOpt in object scala.PartialFunction. From the scaladoc:

def onlyInt(v: Any): Option[Int] = condOpt(v) { case x: Int => x }
like image 64
huynhjl Avatar answered Mar 07 '23 14:03

huynhjl