Is there a more C++ elegant implementation to complete the function jump?

Question

In my daily work, I usually write my code like this：

int ret = 0;
ret = func1();
if(ret != 0) {
  return ret;
}
ret = func2();
if(ret != 0) {
  return ret;
}

But this means I need to complete a lot of "if(ret!=0){return ret;}",Is there a more C++ elegant implementation to complete the function jump? By the way, we are not allowed to use exception.

Answer 1

The shown code seems to be logically equivalent to:

int ret;

if ((ret=func1()) || (ret=func2()))
    return ret;

Tack on as many additional function calls as you wish, in the obvious manner.