Is there a method to check if all array items are '0'?

Question

I have an array

$data = array( 'a'=>'0', 'b'=>'0', 'c'=>'0', 'd'=>'0' );

I want to check if all array values are zero.

if( all array values are '0' ) {

   echo "Got it";

} else {

  echo "No";
}

Thanks

Answer 1

I suppose you could use array_filter() to get an array of all items that are non-zero ; and use empty() on that resulting array, to determine if it's empty or not.

For example, with your example array :

$data = array( 
       'a'=>'0',
       'b'=>'0',
       'c'=>'0',
       'd'=>'0' );

Using the following portion of code :

$tmp = array_filter($data);
var_dump($tmp);

Would show you an empty array, containing no non-zero element :

array(0) {
}

And using something like this :

if (empty($tmp)) {
    echo "All zeros!";
}

Would get you the following output :

All zeros!

On the other hand, with the following array :

$data = array( 
    'a'=>'0', 
    'b'=>'1', 
    'c'=>'0', 
    'd'=>'0' );

The $tmp array would contain :

array(1) {
  ["b"]=>
  string(1) "1"
}

And, as such, would not be empty.

Note that not passing a callback as second parameter to array_filter() will work because (quoting) :

If no callback is supplied, all entries of input equal to FALSE (see converting to boolean) will be removed.

Answer 2

How about:

// ditch the last argument to array_keys if you don't need strict equality
$allZeroes = count( $data ) == count( array_keys( $data, '0', true ) );