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This is a really simple problem, but I couldn't find a solution anywhere.
I'm try to use preg_match or preg_match_all to obtain a string from within parentheses, but without the parentheses.
So far, my expression looks like this:
\([A-Za-z0-9 ]+\)
and returns the following result:
3(hollow highlight) 928-129 (<- original string)
(hollow highlight) (<- result)
What i want is the string within parentheses, but without the parentheses. It would look like this:
hollow highlight
I could probably replace the parentheses afterwards with str_replace or something, but that doesn't seem to be a very elegant solution to me.
What do I have to add, so the parentheses aren't included in the result?
Thanks for your help, you guys are great! :)
959
By placing part of a regular expression inside round brackets or parentheses, you can group that part of the regular expression together. This allows you to apply a quantifier to the entire group or to restrict alternation to part of the regex. Only parentheses can be used for grouping.
The strcmp() function compares two strings. Note: The strcmp() function is binary-safe and case-sensitive. Tip: This function is similar to the strncmp() function, with the difference that you can specify the number of characters from each string to be used in the comparison with strncmp().
The preg_match() function will tell you whether a string contains matches of a pattern.
try:
preg_match('/\((.*?)\)/', $s, $a);
output:
Array
(
[0] => (hollow highlight)
[1] => hollow highlight
)
You just need to add capturing parenthesis, in addition to your escaped parenthesis.
<?php
$in = "hello (world), my name (is andrew) and my number is (845) 235-0184";
preg_match_all('/\(([A-Za-z0-9 ]+?)\)/', $in, $out);
print_r($out[1]);
?>
This outputs:
Array ( [0] => world [1] => is andrew [2] => 845 )
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