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Is it possible to use mysqli_fetch_object with a prepared statement

Tags:

php

mysqli

All the examples I see using mysqli_fetch_object use mysql_query(), I cannot get it to work with prepared statements. Does anyone know what is wrong with this code snippet, as fetch_object returns null.

$sql = "select 1 from dual";
printf("preparing %s\n", $sql);
$stmt = $link->prepare($sql);
printf("prepare statement %s\n", is_null($stmt) ? "is null" : "created");
$rc = $stmt->execute();
printf("num rows is %d\n", $stmt->num_rows);
$result = $stmt->result_metadata();
printf("result_metadata %s\n", is_null($result) ? "is null" : "exists");
$rc = $result->fetch_object();
printf("fetch object returns %s\n", is_null($rc) ? "NULL" : $rc);
$stmt->close();

The output is:

preparing select 1 from dual
prepare statement created
num rows is 0
result_metadata exists
fetch object returns NULL
like image 570
BeWarned Avatar asked Dec 29 '09 19:12

BeWarned


2 Answers

This is the code I use to create an object from a prepared statement.
It could perhaps be used in a subclass of mysqli?

    $query = "SELECT * FROM category WHERE id = ?";
    $stmt = $this->_db->prepare($query);

    $value = 1;
    $stmt->bind_param("i", $value);

    $stmt->execute();

    // bind results to named array
    $meta = $stmt->result_metadata();
    $fields = $meta->fetch_fields();
    foreach($fields as $field) {
        $result[$field->name] = "";
        $resultArray[$field->name] = &$result[$field->name];
    }

    call_user_func_array(array($stmt, 'bind_result'), $resultArray);

    // create object of results and array of objects
    while($stmt->fetch()) {
        $resultObject = new stdClass();

        foreach ($resultArray as $key => $value) {
            $resultObject->$key = $value;
        }

        $rows[] = $resultObject;
    }

    $stmt->close();
like image 52
Zorfling Avatar answered Oct 22 '22 00:10

Zorfling


MySql Native Driver extension (mysqlnd), has the get_result method:

$stmt->execute();
$obj = $stmt->get_result()->fetch_object();
like image 31
peter Avatar answered Oct 21 '22 23:10

peter