I know that this can easily be done in any image editing program, I was just curious if there was a way just using css.
Example:
body {background-color: #837960; background-image: url("Images/background.jpg") background-repeat: no-repeat;}
Could you use css to fade the background image into the background color so a visible line does not exist or should I keep adding a gradient to transparency in Photoshop?
To add transparency, we use the rgba() function to define the color stops. The last parameter in the rgba() function can be a value from 0 to 1, and it defines the transparency of the color: 0 indicates full transparency, 1 indicates full color (no transparency).
CSS gradients allow us to display smooth transitions between two or more colours. They can be added on top of the background image by simply combining the background-image URL and gradient properties.
The linear-gradient() function sets a linear gradient as the background image. To create a linear gradient you must define at least two color stops. Color stops are the colors you want to render smooth transitions among. You can also set a starting point and a direction (or an angle) along with the gradient effect.
It is possible - in CSS3 you can set multiple values for background
body {
background: #837960 url("https://i.stack.imgur.com/MUsp6.jpg") 0 0 no-repeat;
background: -moz-linear-gradient(top, rgba(255,255,255,0) 0%, rgba(130,91,0,1) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(255,255,255,0)), color-stop(100%,rgba(130,91,0,1))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(255,255,255,0) 0%,rgba(130,91,0,1) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(255,255,255,0) 0%,rgba(130,91,0,1) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(255,255,255,0) 0%,rgba(130,91,0,1) 100%); /* IE10+ */
background: linear-gradient(to bottom, rgba(255,255,255,0) 0%,rgba(130,91,0,1) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#00ffffff', endColorstr='#825b00',GradientType=0 ); /* IE6-9 */
}
However, it will work only in modern browser that supports CSS3
(code generated via http://www.colorzilla.com/gradient-editor/)
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