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Is it possible to replace all carriage returns in a string with the .replace function? I've found quite a few complex functions to do it, but was wondering if it could be simplified with just a regex through .replace?
Thanks!
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In the Find box hold down the Alt key and type 0 1 0 for the line feed and Alt 0 1 3 for the carriage return. They can now be replaced with whatever you want.
3.1 The difference between replaceAll() and replace() If search argument is a string, replaceAll() replaces all occurrences of search with replaceWith , while replace() only the first occurence. If search argument is a non-global regular expression, then replaceAll() throws a TypeError exception.
replaceAll() The replaceAll() method returns a new string with all matches of a pattern replaced by a replacement . The pattern can be a string or a RegExp , and the replacement can be a string or a function to be called for each match. The original string is left unchanged.
replaceAll("\\n", ""); s = s. replaceAll("\\r", ""); But this will remove all newlines. Note the double \ 's: so that the string that is passed to the regular expression parser is \n .
Both (new line) and (carraige return) create a new line. To replace all instances of both at the same time: Note that you might want to replace them with a single space rather than nothing. Show activity on this post.
We can also replace text with carriage return by using Keyboard Shortcuts. First of all, select all the cells. I selected here cells B5:C9. Press CTRL + H to have Find & Replace box. Input the Text to be replaced in Find what. Here, I wrote Manchester United to replace. Next, press CTRL + J in Replace with as we want carriage return.
Here, I used the SUBSTITUTE function to Replace the text Manchester United in the C5 cell with a carriage return by using the CHAR function. Now, select cell D5 then click on Wrap Text. Then, we will have the text replaced with a carriage return. Use Fill Handle to AutoFill the rests. You can modify the Row Heights according to your choice. 4.
str = str.replace (/[&r&]/gm,'newChar'); By default, Javascript replace () replaces the first occurance. The way around it is to set the first parameters as a regex.
Both \n (new line) and \r (carraige return) create a new line. To replace all instances of both at the same time:
s.replace(/[\n\r]/g, '');
Note that you might want to replace them with a single space rather than nothing.
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Here how to do it
str = str.replace(/\r/gm,'newChar');
By default, Javascript replace() replaces the first occurance. The way around it is to set the first parameters as a regex.
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