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If I have a function :
@aDecorator
def myfunc1():
# do something here
if __name__ = "__main__":
# this will call the function and will use the decorator @aDecorator
myfunc1()
# now I want the @aDecorator to be replaced with the decorator @otherDecorator
# so that when this code executes, the function no longer goes through
# @aDecorator, but instead through @otherDecorator. How can I do this?
myfunc1()
Is it possible to replace a decorator at runtime?
809
Python allows us to implement more than one decorator to a function. It makes decorators useful for reusable building blocks as it accumulates several effects together. It is also known as nested decorators in Python.
You'll use a decorator when you need to change the behavior of a function without modifying the function itself. A few good examples are when you want to add logging, test performance, perform caching, verify permissions, and so on. You can also use one when you need to run the same code on multiple functions.
A decorator in Python is a function that takes another function as its argument, and returns yet another function . Decorators can be extremely useful as they allow the extension of an existing function, without any modification to the original function source code.
Needless to say, Python's decorators are incredibly useful. Not only can they be used to slow down the time it takes to write some code, but they can also be incredibly helpful at speeding up code. Not only are decorators incredibly useful when you find them about, but it is also a great idea to write your own.
As Miya mentioned, you can replace the decorator with another function any point before the interpreter gets to that function declaration. However, once the decorator is applied to the function, I don't think there is a way to dynamically replace the decorator with a different one. So for example:
@aDecorator
def myfunc1():
pass
# Oops! I didn't want that decorator after all!
myfunc1 = bDecorator(myfunc1)
Won't work, because myfunc1 is no longer the function you originally defined; it has already been wrapped. The best approach here is to manually apply the decorators, oldskool-style, i.e:
def myfunc1():
pass
myfunc2 = aDecorator(myfunc1)
myfunc3 = bDecorator(myfunc1)
Edit: Or, to be a little clearer,
def _tempFunc():
pass
myfunc1 = aDecorator(_tempFunc)
myfunc1()
myfunc1 = bDecorator(_tempFunc)
myfunc1()
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