I know it's perfectly possible to initialise a char
array with a string literal:
char arr[] = "foo";
C++11 8.5.2/1 says so:
A
char
array (whether plainchar
,signed char
, orunsigned char
),char16_t
array,char32_t
array, orwchar_t
array can be initialized by a narrow character literal,char16_t
string literal,char32_t
string literal, or wide string literal, respectively, or by an appropriately-typed string literal enclosed in braces. Successive characters of the value of the string literal initialize the elements of the array. ...
However, can you do the same with two string literals in a conditional expression? For example like this:
char arr[] = MY_BOOLEAN_MACRO() ? "foo" : "bar";
(Where MY_BOOLEAN_MACRO()
expands to a 1
or 0
).
The relevant parts of C++11 5.16 (Conditional operator) are as follows:
1 ... The first expression is contextually converted to
bool
(Clause 4). It is evaluated and if it istrue
, the result of the conditional expression is the value of the second expression, otherwise that of the third expression. ...4 If the second and third operands are glvalues of the same value category and have the same type, the result is of that type and value category and it is a bit-field if the second or the third operand is a bit-field, or if both are bit-fields.
Notice that the literals are of the same length and thus they're both lvalues of type const char[4]
.
GCC one ideone accepts the construct. But from reading the standard, I am simply not sure whether it's legal or not. Does anyone have better insight?
You can initialize a one-dimensional character array by specifying: A brace-enclosed comma-separated list of constants, each of which can be contained in a character. A string constant (braces surrounding the constant are optional)
A more convenient way to initialize a C string is to initialize it through character array: char char_array[] = "Look Here"; This is same as initializing it as follows: char char_array[] = { 'L', 'o', 'o', 'k', ' ', 'H', 'e', 'r', 'e', '\0' };
String refers to a sequence of characters represented as a single data type. Character Array is a sequential collection of data type char. Strings are immutable.
String literals are stored in C as an array of chars, terminted by a null byte.
On the other hand clang
does not accept such code (see it live) and I believe clang
is correct on this (MSVC also rejects this code ).
A string literal is defined by the grammar in section 2.14.5
:
string-literal:
encoding-prefixopt" s-char-sequenceopt"
encoding-prefixoptR raw-string
and the first paragraph from this section says (emphasis mine):
A string literal is a sequence of characters (as defined in 2.14.3) surrounded by double quotes, optionally prefixed by R, u8, u8R, u, uR, U, UR, L, or LR, as in "...", R"(...)", u8"...", u8R"(...)", u"...", uR"˜(...)˜", U"...", UR"zzz(...)zzz", L"...", or LR"(...)", respectively
and it further says that the type of a narrow string literal is:
“array of n const char”,
as well as:
has static storage duration
but an “array of n const char”, with static storage duration is not a string literal since it does not fit the grammar nor does it fit paragraph 1
.
We can make this fail on gcc
if we use a non-constant expression (see it live):
bool x = true ;
char arr[] = x ? "foo" : "bar";
which means it is probably an extension, but it is non-conforming since it does not produce a warning in strict conformance mode i.e. using -std=c++11 -pedantic
. From section 1.4
[intro.compliance]:
[...]Implementations are required to diagnose programs that use such extensions that are ill-formed according to this International Standard. Having done so, however, they can compile and execute such programs.
This works in GCC in C++11 or newer because the literals you're providing are deterministic during compile time (eg, they are constexpr
). Since the compiler can figure out which one is true, it is allowed to figure out which one to use.
To remove the constexpr
ability, try something like this:
#include <iostream>
#include <cstdlib>
int main() {
bool _bool = rand();
char arr[] = (_bool) ? "asdf" : "ffff";
std::cout << arr << std::endl;
}
GCC then errors out with:
g++ test.cpp -std=c++11
test.cpp: In function ‘int main()’:
test.cpp:6:34: error: initializer fails to determine size of ‘arr’
char arr[] = (_bool) ? "asdf" : "ffff";
^
test.cpp:6:34: error: array must be initialized with a brace-enclosed initializer
I don't know the standard's text definition well enough to know where or why this is valid, but I feel that it is valid.
For further reading on constexpr
and how it can impact compilability, see the answer by @ShafikYaghmour in another question.
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