If I do python -m SimpleHTTPServer
it serves the files in the current directory.
My directory structure looks like this:
/protected/public
/protected/private
/test
I want to start the server in my /test
directory and I want it to serve files in the /test
directory. But I want all requests to the server starting with '/public' to be pulled from the /protected/public
directory.
e.g.a request to http://localhost:8000/public/index.html
would serve the file at /protected/public/index.html
Is this possible with the built in server or will I have to write a custom one?
I think it is absolutely possible to do that. You can start the server inside /test
directory and override translate_path
method of SimpleHTTPRequestHandler
as follows:
import BaseHTTPServer
import SimpleHTTPServer
server_address = ("", 8888)
PUBLIC_RESOURCE_PREFIX = '/public'
PUBLIC_DIRECTORY = '/path/to/protected/public'
class MyRequestHandler(SimpleHTTPServer.SimpleHTTPRequestHandler):
def translate_path(self, path):
if self.path.startswith(PUBLIC_RESOURCE_PREFIX):
if self.path == PUBLIC_RESOURCE_PREFIX or self.path == PUBLIC_RESOURCE_PREFIX + '/':
return PUBLIC_DIRECTORY + '/index.html'
else:
return PUBLIC_DIRECTORY + path[len(PUBLIC_RESOURCE_PREFIX):]
else:
return SimpleHTTPServer.SimpleHTTPRequestHandler.translate_path(self, path)
httpd = BaseHTTPServer.HTTPServer(server_address, MyRequestHandler)
httpd.serve_forever()
Hope this helps.
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