Today I found this post on Quora, which claimed that
factorial(n) = def $ do
assert (n<=0) "Negative factorial"
ret <- var 1
i <- var n
while i $ do
ret *= i
i -= 1
return ret
could be correct Haskell code. I got curious, and ended up with
factorial :: Integer -> Integer
factorial n = def $ do
assert (n >= 0) "Negative factorial"
ret <- var 1
i <- var n
while i $ do
ret *= i
i -= 1
return ret
using var = newSTRef
, canonical definitions for def
, assert
and while
, and
a *= b = readSTRef b >>= \b -> modifySTRef a ((*) b)
a -= b = modifySTRef a ((+) (negate b))
However, (*=)
and (-=)
have different types:
(-=) :: Num a => STRef s a -> a -> ST s ()
(*=) :: Num a => STRef s a -> STRef s a -> ST s ()
So ret -= i
wouldn't work. I've tried to create a fitting type class for this:
class (Monad m) => NumMod l r m where
(+=) :: l -> r -> m ()
(-=) :: l -> r -> m ()
(*=) :: l -> r -> m ()
instance Num a => NumMod (STRef s a) (STRef s a) (ST s) where
a += b = readSTRef b >>= \b -> modifySTRef a ((+) b)
a -= b = readSTRef b >>= \b -> modifySTRef a ((+) (negate b))
a *= b = readSTRef b >>= \b -> modifySTRef a ((*) b)
instance (Num a) => NumMod (STRef s a) a (ST s) where
a += b = modifySTRef a ((+) (b))
a -= b = modifySTRef a ((+) (negate b))
a *= b = modifySTRef a ((*) (b))
That actually works, but only as long as factorial
returns an Integer
. As soon as I change the return type to something else it fails. I've tried to create another instance
instance (Num a, Integral b) => NumMod (STRef s a) b (ST s) where
a += b = modifySTRef a ((+) (fromIntegral $ b))
a -= b = modifySTRef a ((+) (negate . fromIntegral $ b))
a *= b = modifySTRef a ((*) (fromIntegral b))
which fails due to overlapping instances.
Is it actually possible to create a fitting typeclass and instances to get the factorial
running for any Integral a
? Or will this problem always occur?
Idea is simple: wrap STRef s a
in a new data type and make it an instance of Num
.
First, we'll need only one pragma:
{-# LANGUAGE RankNTypes #-}
import Data.STRef (STRef, newSTRef, readSTRef, modifySTRef)
import Control.Monad (when)
import Control.Monad.ST (ST, runST)
Wrapper for STRef
:
data MyRef s a
= MySTRef (STRef s a) -- reference (can modify)
| MyVal a -- pure value (modifications are ignored)
instance Num a => Num (MyRef s a) where
fromInteger = MyVal . fromInteger
A few helpers for MyRef
to resemble STRef
functions:
newMyRef :: a -> ST s (MyRef s a)
newMyRef x = do
ref <- newSTRef x
return (MySTRef ref)
readMyRef :: MyRef s a -> ST s a
readMyRef (MySTRef x) = readSTRef x
readMyRef (MyVal x) = return x
I'd like to implement -=
and *=
using a bit more general alter
helper:
alter :: (a -> a -> a) -> MyRef s a -> MyRef s a -> ST s ()
alter f (MySTRef x) (MySTRef y) = readSTRef y >>= modifySTRef x . flip f
alter f (MySTRef x) (MyVal y) = modifySTRef x (flip f y)
alter _ _ _ = return ()
(-=) :: Num a => MyRef s a -> MyRef s a -> ST s ()
(-=) = alter (-)
(*=) :: Num a => MyRef s a -> MyRef s a -> ST s ()
(*=) = alter (*)
Other functions are almost unchanged:
var :: a -> ST s (MyRef s a)
var = newMyRef
def :: (forall s. ST s (MyRef s a)) -> a
def m = runST $ m >>= readMyRef
while :: (Num a, Ord a) => MyRef s a -> ST s () -> ST s ()
while i m = go
where
go = do
n <- readMyRef i
when (n > 0) $ m >> go
assert :: Monad m => Bool -> String -> m ()
assert b str = when (not b) $ error str
factorial :: Integral a => a -> a
factorial n = def $ do
assert (n >= 0) "Negative factorial"
ret <- var 1
i <- var n
while i $ do
ret *= i
i -= 1
return ret
main :: IO ()
main = print . factorial $ 1000
Making Num
instances like this feels a bit hacky, but we don't have FromInteger
type class in Haskell, so I guess it's OK.
Another itchy thing is 3 *= 10
which is return ()
. I think it is possible to use phantom type to indicate whether MyRef
is ST
or pure and allow only ST
on the LHS of alter
.
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