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Let's imagine I have a bash script, where I call this:
bash -c "some_command" do something with code of some_command here Is it possible to obtain the code of some_command? I'm not executing some_command directly in the shell running the script because I don't want to alter it's environment.
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Use signals to exit process from subshell This is the mechanism that allows you to exit a command line process by pressing ctrl-c. When you press ctrl-c in your terminal, an interrupt signal (SIGINT) is sent to the current process.
To check the exit code we can simply print the $? special variable in bash. This variable will print the exit code of the last run command.
Launch a terminal, and run any command. Check the value of the shell variable “$?” for the exit code. $ echo $? As the “date” command ran successfully, the exit code is 0.
Use return . The return bash builtin will exit the sourced script without stopping the calling (parent/sourcing) script. Causes a function to stop executing and return the value specified by n to its caller.
$? will contain the return code of some_command just as usual.
Of course it might also contain a code from bash, in case something went wrong before your command could even be executed (wrong filename, whatnot).
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