Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Is it possible to generate and return a ZIP file with App Engine?

Tags:

I have a small project that would be perfect for Google App Engine. Implementing it hinges on the ability to generate a ZIP file and return it.

Due to the distributed nature of App Engine, from what I can tell, the ZIP file couldn't be created "in-memory" in the traditional sense. It would basically have to be generated and and sent in a single request/response cycle.

Does the Python zip module even exist in the App Engine environment?

like image 864
Soviut Avatar asked Feb 24 '09 21:02

Soviut


People also ask

How do you created a Zip file?

Right-click on the file or folder.Select “Compressed (zipped) folder”. To place multiple files into a zip folder, select all of the files while hitting the Ctrl button. Then, right-click on one of the files, move your cursor over the “Send to” option and select “Compressed (zipped) folder”.

What program creates zip files?

WinZip is a zip tool program that can be used to compress and decompress files with no hassle. It enables you to zip large files to send as an attachment to the email. Feature: It can unzip all major file formats, including zip, gzip tar, rar, cab, etc.

How do I create a zip file and save it?

To zip (compress) a file or folderPress and hold (or right-click) the file or folder, select (or point to) Send to, and then select Compressed (zipped) folder. A new zipped folder with the same name is created in the same location.


1 Answers

zipfile is available at appengine and reworked example follows:

from contextlib import closing
from zipfile import ZipFile, ZIP_DEFLATED

from google.appengine.ext import webapp
from google.appengine.api import urlfetch

def addResource(zfile, url, fname):
    # get the contents      
    contents = urlfetch.fetch(url).content
    # write the contents to the zip file
    zfile.writestr(fname, contents)

class OutZipfile(webapp.RequestHandler):
    def get(self):
        # Set up headers for browser to correctly recognize ZIP file
        self.response.headers['Content-Type'] ='application/zip'
        self.response.headers['Content-Disposition'] = \
            'attachment; filename="outfile.zip"'    

        # compress files and emit them directly to HTTP response stream
        with closing(ZipFile(self.response.out, "w", ZIP_DEFLATED)) as outfile:
            # repeat this for every URL that should be added to the zipfile
            addResource(outfile, 
                'https://www.google.com/intl/en/policies/privacy/', 
                'privacy.html')
            addResource(outfile, 
                'https://www.google.com/intl/en/policies/terms/', 
                'terms.html')
like image 183
myroslav Avatar answered Sep 16 '22 18:09

myroslav