Apologies for my poor wording of the question. I've tried searching for an answer but not knowing what to search is making it very difficult to find one.
Here is a simple function which calculates the area of a triangle.
triangleArea :: Float -> Float -> Float -> Float
triangleArea a b c
| (a + b) <= c = error "Not a triangle!"
| (a + c) <= b = error "Not a triangle!"
| (b + c) <= a = error "Not a triangle!"
| otherwise = sqrt (s * (s - a) * (s - b) * (s - c))
where s = (a + b + c) / 2
Three lines of the function have been taken up for the purposes of error checking. I was wondering if these three lines could be condensed into one generic line.
I was wondering if something similar to the following would be possible
(arg1 + arg2) == arg3
where Haskell knows to check each possible combination of the three arguments.
I think @behzad.nouri's comment is the best. Sometimes doing a little math is the best way to program. Here's a somewhat overdone expansion on @melpomene's solution, which I thought would be fun to share. Let's write a function similar to permutations but that computes combinations:
import Control.Arrow (first, second)
-- choose n xs returns a list of tuples, the first component of each having
-- n elements and the second component having the rest, in all combinations
-- (ignoring order within the lists). N.B. this would be faster if implemented
-- using a DList.
choose :: Int -> [a] -> [([a],[a])]
choose 0 xs = [([], xs)]
choose _ [] = []
choose n (x:xs) =
map (first (x:)) (choose (n-1) xs) ++
map (second (x:)) (choose n xs)
So..
ghci> choose 2 [1,2,3]
[([1,2],[3]),([1,3],[2]),([2,3],[1])]
Now you can write
triangleArea a b c
| or [ x + y <= z | ([x,y], [z]) <- choose 2 [a,b,c] ] = error ...
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