Is it possible to declare a function type that uses itself as an argument in C++?

Question

For instance, is there any legal equivalent to this?

typedef void (*SelfReferencingFnPtr)(int, SelfReferencingFnPtr);

With clang, this causes the error "unknown name SelfReferencingFnPtr".

The best I was able to come up with is a functor whose operator() accepts its own type.

Answer 1

No, see GotW #57. It's indeed a recursive problem.