Complexity :- O(n) as copy() takes linear time to traverse elements. But begin(),end() and back_inserter() takes constant time. This function takes 2 arguments, first iterator to old vector and last iterator to old vector. It then assigns values of old vector to new vector.
A vector<int> is not same as int[] (to the compiler). vector<int> is non-array, non-reference, and non-pointer - it is being passed by value, and hence it will call copy-constructor. So, you must use vector<int>& (preferably with const , if function isn't modifying it) to pass it as a reference.
Using std::copy functionThe standard algorithm for copying is std::copy . We can use it for copying elements from the source vector to the destination vector.
They aren't the same though, are they? One is a copy, the other is a swap. Hence the function names.
My favourite is:
a = b;
Where a
and b
are vectors.
Your second example does not work if you send the argument by reference. Did you mean
void copyVecFast(vec<int> original) // no reference
{
vector<int> new_;
new_.swap(original);
}
That would work, but an easier way is
vector<int> new_(original);
This is another valid way to make a copy of a vector, just use its constructor:
std::vector<int> newvector(oldvector);
This is even simpler than using std::copy
to walk the entire vector from start to finish to std::back_insert
them into the new vector.
That being said, your .swap()
one is not a copy, instead it swaps the two vectors. You would modify the original to not contain anything anymore! Which is not a copy.
=
operatorWe can use the public member function std::vector::operator=
of the container std::vector
for assigning values from a vector to another.
Besides, a constructor function also makes sense. A constructor function with another vector as parameter(e.g. x
) constructs a container with a copy of each of the elements in x
, in the same order.
std::vector::swap
std::vector::swap
is not copying a vector to another, it is actually swapping elements of two vectors, just as its name suggests. In other words, the source vector to copy from is modified after std::vector::swap
is called, which is probably not what you are expected.
If the elements in the source vector are pointers to other data, then a deep copy is wanted sometimes.
According to wikipedia:
A deep copy, meaning that fields are dereferenced: rather than references to objects being copied, new copy objects are created for any referenced objects, and references to these placed in B.
Actually, there is no currently a built-in way in C++ to do a deep copy. All of the ways mentioned above are shallow. If a deep copy is necessary, you can traverse a vector and make copy of the references manually. Alternatively, an iterator can be considered for traversing. Discussion on iterator is beyond this question.
The page of std::vector
on cplusplus.com
new_vector.assign(old_vector.begin(),old_vector.end()); // Method 1
new_vector = old_vector; // Method 2
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