Recently, I have been developing a practice of making many things in my code as const
:
(1) Arguments to function, which I know never going to be changed. e.g.:
void foo (const int i, const string s)
^^^^^ ^^^^^
(2) Return types as const
. e.g.:
struct A {
...
const int foo () { return ...; }
^^^^^
operator const bool () const { return ...; }
^^^^^
};
(3) Trivial computation of integer or strings. e.g.:
const uint size = vec.size();
^^^^^
const string s2 = s1 + "hello ";
^^^^^
... and few more places. Typically in other real world codes, I don't see such small scale variables marked as const
. But I thought, making them const
will never harm. Is it a good programming practice ?
(1) and (3) are closely related. A by-value parameter is just a local variable with that name, as is the result of your computation.
Usually it makes little difference in short functions whether you mark local variables const
or not, since you can see their entire scope right in front of you. You can see whether or not the value changes, you don't need or want the compiler to enforce it.
Occasionally it does help, however, since it protects you from accidentally passing them to a function that takes its parameter by non-const reference, without realising that you're modifying your variable. So if you pass the variable as a function argument during its life, then marking it const
can give you more confidence that you know what value it has afterwards.
Very occasionally, marking a variable const
can help the optimizer, since you're telling it that the object is never modified, and sometimes that's true but the compiler can't otherwise prove it. But it's probably not worth doing it for that reason, because in most cases it makes no difference.
(2) is another matter. For built-in types it makes no difference, as others have explained. For class types, do not return by const value. It might seem like a good idea, in that it prevents the user writing something pointless like func_returning_a_string() += " extra text";
. But it also prevents something which is pointful -- C++11 move semantics. If foo
returns a const string, and I write std::string s = "foo"; if (condition) s = foo();
, then I get copy assignment at s = foo();
. If foo
returns a non-const string then I get move assignment.
Similarly in C++03, which doesn't have move semantics, it prevents the trick known as "swaptimization" - with a non-const return value I can write foo().swap(s);
instead of s = foo();
.
Yes.
It is always a good programming practice to express your intents in the programming language. You don't intend to change the variable, so make it const. Later on, when your compiler yells at you that you can't modify it when it is const, you will be happy that the compiler spotted some wrong ideas of your own design. This is not only true for const, but also for many other things, which is e.g. why in C++11 the override
keyword was introduced.
Of course there are cases where const will not change anything, like when you return an int
, but just like in other safety areas: better to have one const too much (that you might remove later because it wasn't really needed), than to have one too little (which will suddenly break stuff silently).
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