Is 1[&array] a proper replacement for &array[sizeof(array)/sizeof(array[0])] or way too obfuscated?

Question

C has no elementsof keyword to get the element count of an array. So this is commonly replaced by calculateing sizeof(Array)/sizeof(Array[0]) but this needs repeating the array variable name. 1[&Array] is the pointer to the first element right after the array, so you could use:

int myArray[12] = {1,2,3};  
int *pElement;

for (pElement = myArray; pElement < 1[&myArray]; pElement++)
{
  ...
}

to replace:

for (pElement = myArray; pElement < &myArray[sizeof(myArray)/sizeof(myArray[0])]; pElement++)
{
  ...
}

do you think this is too obfuscated?

Answer 1

1[&myArray] is non-obvious. I suggest that you use temporary variables:

size_t count = sizeof array / sizeof *array;
int * const end = &array[count];
for (pElement = myArray; pElement < end; pElement++)

Or rather just use standard index variable:

size_t count = sizeof array / sizeof *array;
for(size_t i=0; i<count; ++i) {
    int *pElement = &array[i];

What ever you do, use temporary variables, because you can name them descriptively. It will make reading the code much faster, without affecting runtime performance (unless compiler is braindead).