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iphone low pass filter

I'm trying to implement a low-pass filter for an iphone app where I record a sound and then it gets played back slightly muffled; like the voice is coming from another room.

I've looked into the different options for audio recording and manipulation and have found it a bit confusing...digital signal processing isn't a strong point at all. I've mainly looked into OpenAL and inside the EFX library there is a filter that specifically does what I need, but EFX is not included on the iPhone. Is there a way of replicating that behaviour using OpenAL for the iPhone? Is there another option such as Audio Units that could provide a solution?

Thanks for your help

EDIT:

So after Tom's answer and links, I've come up with what I think is a correct implementation. However, I'm not getting a muffling effect at all, rather just a decrease in volume. Here's the (summarised) code I have currently:

File is recorded using AVAudioRecorder and the following settings:

[recordSetting setValue :[NSNumber numberWithInt:kAudioFormatLinearPCM] forKey:AVFormatIDKey];
[recordSetting setValue:[NSNumber numberWithFloat:44100] forKey:AVSampleRateKey];
[recordSetting setValue:[NSNumber numberWithInt: 1] forKey:AVNumberOfChannelsKey];

[recordSetting setValue :[NSNumber numberWithInt:16] forKey:AVLinearPCMBitDepthKey];
[recordSetting setValue :[NSNumber numberWithBool:NO] forKey:AVLinearPCMIsBigEndianKey];
[recordSetting setValue :[NSNumber numberWithBool:NO] forKey:AVLinearPCMIsFloatKey];

I then read in the file and transform it with the code below:

// Read in the file using AudioFileOpenURL
AudioFileID fileID = [self openAudioFile:filePath];

// find out how big the actual audio data is
UInt32 fileSize = [self audioFileSize:fileID];

// allocate the memory to hold the file
SInt16 * outData = (SInt16 *)malloc(fileSize); 

// Read in the file to outData
OSStatus result = noErr;
result = AudioFileReadBytes(fileID, false, 0, &fileSize, outData);

// close off the file
AudioFileClose(fileID);

// Allocate memory to hold the transformed values
SInt16 * transformData = (SInt16 *)malloc(fileSize);

// Start the transform - Need to set alpha to 0.15 or below to have a noticeable affect
float alpha = 1;         

// Code as per Tom's example
transformData[0] = outData[0];

for(int sample = 1; sample < fileSize / sizeof(SInt16); sample ++) 
{
     transformData[sample] = transformData[sample - 1] + alpha * (outData[sample] - transformData[sample - 1]);
}

// Add the data to OpenAL buffer
NSUInteger bufferID;
// grab a buffer ID from openAL
alGenBuffers(1, &bufferID);

// Add the audio data into the new buffer
alBufferData(bufferID,AL_FORMAT_MONO16,transformData,fileSize,44100);

So after all that, I then play it through OpenAL using the standard method (I don't think it has any impact on my results so I won't include it here.)

I've traced through the results, both before and after transform, and they seem correct to me i.e. the values before vary positively and negatively as I would expect and the for loop is definitely flattening out those values. But as I mentioned before I'm only seeing (what seems to me) a reduction in volume, so I'm able to increase the gain and cancel out what I've just done.

It seems that I must be working on the wrong values. Any suggestions of what I'm doing wrong here?

like image 622
swingdoctor Avatar asked Dec 22 '10 01:12

swingdoctor


People also ask

What does low pass do?

What is a low-pass filter? A low-pass filter (LPF) is an audio signal processor that removes unwanted frequencies from a signal above a determined cutoff frequency. It progressively filters out (attenuates) the high-end above its cutoff frequency while allowing the low-end to pass through, ideally without any changes.

How do you use low pass?

As an experiment, place a low-pass filter on the output channel of a session, then pull the cutoff down towards its lowest point. You'll notice the vibrancy of the mix leaving (especially once you surpass 15 kHz), until all you're left with is a murky low-end soup.


1 Answers

Tom's answer is the following recursive filter:

y[n] = (1 - a)*y[n-1] + a*x[n]

H(z) = Y(z)/X(z) = a / (1 - (1 - a)*1/z)

I'll plot this in Python/pylab for a=0.25, a=0.50, and a=0.75:

from pylab import *

def H(a, z):
    return a / (1 - (1 - a) / z)

w = r_[0:1000]*pi/1000
z = exp(1j*w)
H1 = H(0.25, z)
H2 = H(0.50, z)
H3 = H(0.75, z)
plot(w, abs(H1), 'r') # red
plot(w, abs(H2), 'g') # green
plot(w, abs(H3), 'b') # blue

alt text

Pi radians/sample is the Nyquist frequency, which is half the sampling frequency.

If this simple filter is inadequate, try a 2nd order Butterworth filter:

# 2nd order filter:
# y[n] = -a[1]*y[n-1] - a[2]*y[n-2] + b[0]*x[n] + b[1]*x[n-1] + b[2]*x[n-2]

import scipy.signal as signal

# 2nd order Butterworth filter coefficients b,a
# 3dB cutoff = 2000 Hz
fc = 2000.0/44100
b, a = signal.butter(2, 2*fc)

# b = [ 0.01681915,  0.0336383 ,  0.01681915]
# a = [ 1.        , -1.60109239,  0.66836899]

# approximately:
# y[n] = 1.60109*y[n-1] - 0.66837*y[n-2] + 
#        0.01682*x[n] + 0.03364*x[n-1] + 0.01682*x[n-2]

# transfer function
def H(b,a,z):
    num = b[0] + b[1]/z + b[2]/(z**2)
    den = a[0] + a[1]/z + a[2]/(z**2)
    return num/den

H4 = H(b, a, z)
plot(w, abs(H4))
# show the corner frequency
plot(2*pi*fc, sqrt(2)/2, 'ro')  
xlabel('radians')

alt text

Evaluate a test signal at the 3dB cutoff frequency fc=2000:

fc = 2000.0/44100
b, a = signal.butter(2, 2*fc)

# test signal at corner frequency (signed 16-bit)
N = int(5/fc)  # sample for 5 cycles
x = int16(32767 * cos(2*pi*fc*r_[0:N]))

# signed 16-bit output
yout = zeros(size(x), dtype=int16)

# temp floats
y  = 0.0    
y1 = 0.0
y2 = 0.0

# filter the input
for n in r_[0:N]:
    y = (-a[1] * y1 + 
         -a[2] * y2 + 
          b[0] * x[n]   + 
          b[1] * x[n-1] + 
          b[2] * x[n-2])
    # convert to int16 and saturate
    if y > 32767.0:    yout[n] = 32767
    elif y < -32768.0: yout[n] = -32768
    else:              yout[n] = int16(y)
    # shift the variables
    y2 = y1
    y1 = y

# plots
plot(x,'r')       # input in red
plot(yout,'g')    # output in green
# show that this is the 3dB point
plot(sqrt(2)/2 * 32768 * ones(N),'b-')
xlabel('samples')

alt text

like image 174
Eryk Sun Avatar answered Nov 15 '22 13:11

Eryk Sun