Would it be possible to share a picture to Instagram bypassing the Action Share Sheet?
Please Note that I am aware of the UIDocumentInteractionController
and the hooks and in fact it works fine. With their sample code you get a Copy to Instagram
option (either unique if you use the exclusive UTI or a big list of apps which can handle a JPG/PNG, alongside with Instagram).
This works fine, but I'd like to know if there's a way to execute the action "Copy to Instagram" without the need to present the UIDocumentInteractionController
menu in iOS 9+.
For the record this is a simplified version of the code that works perfectly. Assuming you have a valid NSURL…
guard let data: NSData = NSData(contentsOfURL: url),
image = UIImage(data: data) else {
return
}
let imageData = UIImageJPEGRepresentation(image, 100)
let captionString = "caption"
let writePath = (NSTemporaryDirectory() as NSString).stringByAppendingPathComponent("instagram.ig")
guard let _ = imageData?.writeToFile(writePath, atomically: true) else {
return
}
let fileURL = NSURL(fileURLWithPath: writePath)
self.documentController = UIDocumentInteractionController(URL: fileURL)
self.documentController.delegate = self
self.documentController.UTI = "com.instagram.photo"
self.documentController.annotation = NSDictionary(object: captionString, forKey: "InstagramCaption")
self.documentController.presentOpenInMenuFromRect(viewController.view.frame, inView: viewController.view, animated: true)
The problem is that this will present an "Action Sheet" and I want to avoid doing that if possible, I want to use instagram.ige
(or whatever the name it was to make it exclusive) and skip this ActionSheet.
Is that possible?
UPDATE: I haven't found a solution for this, but seems like Instagram finally is adding/added extensions: "Instagram recently added sharing extensions functionality to its iOS app. Now, you can share photos from third-party apps directly to Instagram" source: http://www.macworld.com/article/3080038/data-center-cloud/new-instagram-feature-for-ios-makes-it-easier-to-share-photos-from-other-apps.html
UPDATED Swift 4.2 CODE
import Photos
func postImageToInstagram(image: UIImage) {
UIImageWriteToSavedPhotosAlbum(
image,
self,
#selector(self.image(image:didFinishSavingWithError:contextInfo:)),
nil
)
}
@objc func image(image: UIImage, didFinishSavingWithError error: NSError?, contextInfo: UnsafeRawPointer) {
if let err = error {
print(err) // TODO: handle error
return
}
let fetchOptions = PHFetchOptions()
fetchOptions.sortDescriptors = [NSSortDescriptor(key: "creationDate", ascending: false)]
let fetchResult = PHAsset.fetchAssets(with: .image, options: fetchOptions)
if let lastAsset = fetchResult.firstObject {
let localIdentifier = lastAsset.localIdentifier
let u = "instagram://library?AssetPath=" + localIdentifier
let url = URL(string: u)!
if UIApplication.shared.canOpenURL(url) {
UIApplication.shared.open(url, options: [:], completionHandler: nil)
} else {
let alertController = UIAlertController(title: "Error", message: "Instagram is not installed", preferredStyle: .alert)
alertController.addAction(UIAlertAction(title: "OK", style: .default, handler: nil))
self.present(alertController, animated: true, completion: nil)
}
}
}
Original Answer
import Photos
...
func postImageToInstagram(image: UIImage) {
UIImageWriteToSavedPhotosAlbum(image, self, #selector(SocialShare.image(_:didFinishSavingWithError:contextInfo:)), nil)
}
func image(image: UIImage, didFinishSavingWithError error: NSError?, contextInfo:UnsafePointer<Void>) {
if error != nil {
print(error)
}
let fetchOptions = PHFetchOptions()
fetchOptions.sortDescriptors = [NSSortDescriptor(key: "creationDate", ascending: false)]
let fetchResult = PHAsset.fetchAssetsWithMediaType(.Image, options: fetchOptions)
if let lastAsset = fetchResult.firstObject as? PHAsset {
let localIdentifier = lastAsset.localIdentifier
let u = "instagram://library?LocalIdentifier=" + localIdentifier
let url = NSURL(string: u)!
if UIApplication.sharedApplication().canOpenURL(url) {
UIApplication.sharedApplication().openURL(NSURL(string: u)!)
} else {
let alertController = UIAlertController(title: "Error", message: "Instagram is not installed", preferredStyle: .Alert)
alertController.addAction(UIAlertAction(title: "OK", style: .Default, handler: nil))
self.presentViewController(alertController, animated: true, completion: nil)
}
}
}
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