Invoke a method with a timeout

Question

What I want to is invoking a method foo() with a timeout (say 1 minute). If its execution costs less than 1 minute, return the result. Otherwise an exception will be thrown. Here is the code:

//PRINT "START" IN THE LOG
auto m = std::make_shared<std::mutex>();
auto cv = std::make_shared<std::condition_variable>();
auto ready = std::make_shared<bool>(false);
auto response = std::make_shared<TResponse>();
auto exception = std::make_shared<FooException>();
exception->Code = ErrorCode::None;

std::thread([=]
{
    std::unique_lock<std::mutex> lk(*m);
    cv->wait(lk, [=]{ return *ready; });

    try
    {
        //PRINT "PROCESS" IN THE LOG
        auto r = foo();
        *response = std::move(r);
    }
    catch(const FooException& e)
    {
        *exception = std::move(e);
    }

    lk.unlock();
    cv->notify_one();
}).detach();

std::unique_lock<std::mutex> lk(*m);
*ready = true;
cv->notify_one();
auto status = cv->wait_for(lk, std::chrono::seconds(60));
if (status == std::cv_status::timeout)
{
    //PRINT "TIMEOUT" IN THE LOG
    //throw timeout exception
}
else
{
    //PRINT "FINISH" IN THE LOG
    if (exception->Code == ErrorCode::None)
    {
        return *response;
    }
    else
    {
        throw *exception;
    }
}

You can see I add logs START/PROCESS/FINISH/TIMEOUT in the code, every time this method is executed, I can see START/PROCESS/FINISH or START/PROCESS/TIMEOUT pattern in the logs. However, sometimes the logs are START/PROCESS, without any FINISH/TIMEOUT. I think cv->wait_for should block the current thread for 60 seconds at most, then it exists with either TIMEOUT or FINISH.

The foo() method contains disk IO operations to network drives that sometimes hangs for more than 1 hour(the reason is not related to this question, and it can't be resolved now), I tried to replace foo with a thread sleep, everything is working as expected. What's wrong with this code and how can I improve this?

Answer 1

Because you have no predicate in the cv->wait_for call, the thread might be unblocked spuriously. However, it is strange that no FINISH/TIMEOUT is printed. So we might need more information here: What does happen with the program? Does it hang, does it throw, does it just exit, does it print in the line after cv->wait_for?

You could try using std::async and see if the same behavior appears (furthermore, it would greatly simplify your code):

std::future<int> res = std::async(foo);

std::future_status stat = res.wait_for(std::chrono::seconds(60));

if (stat != std::future_status::ready) {
  std::cout << "Timed out..." << "\n";
} else {
  try {
    int result = res.get();
    std::cout << "Result = " << result << std::endl;
  } catch (const FooException& e) {
    std::cerr << e.what() << '\n';
  }
}

---

EDIT As pointed out in the comments by CuriouslyRecurringThoughts the future of std::async blocks in the destructor. If that is not an option, the following code uses a std::promise and a detached thread instead:

std::promise<int> prom;
std::future<int> res = prom.get_future();

std::thread([p = std::move(prom)]() mutable {
  try {
    p.set_value(foo());
  } catch (const std::exception& e) {
    p.set_exception(std::current_exception());
  }
}).detach();

Waiting for the std::future is done as shown before.

Answer 2

It seems that despite the timed wait your main thread deadlocks because even when cv->wait_for returns with timeout it still tries to lk.lock() on the mutex which is currently locked by the second thread.

As mentioned on cppreference about wait_for:

When unblocked, regardless of the reason, lock is reacquired and wait_for() exits.

I'm not sure why the promise/future solution didn't work for you since you didn't post that example here, but I've tried a simple version of it which seems to work even when the second thread "hangs":

using namespace std::chrono_literals;

std::cout << "START" << std::endl;
std::promise<void> p;
auto f = p.get_future();
std::thread t([p = std::move(p)]() mutable {
    std::cout << "PROCESS" << std::endl;
    std::this_thread::sleep_for(5min);
    p.set_value();
});

auto status = f.wait_for(5s);
std::cout << (status == std::future_status::ready ? "FINISH" : "TIMEOUT") << std::endl;
t.join();

The output is as expected:

START
PROCESS
TIMEOUT

Answer 3

We can create a separate thread to run the call itself, and wait on a condition variable back in your main thread which will be signaled by the thread doing the call to foo once it returns.

The trick is to wait on the condition variable with your 60s timeout, so that if the call takes longer than the timeout you will still wake up, know about it, and be able to throw the exception - all in the main thread.

Please find below a code example:

#include <iostream>
#include <chrono>
#include <thread>
#include <mutex>
#include <condition_variable>

using namespace std::chrono_literals;

int foo()
{

    //std::this_thread::sleep_for(10s); //Will Return  Success
    std::this_thread::sleep_for(70s); //Will Return  Timeout
    return 1;
}

int foo_wrapper()
{
    std::mutex m;
    std::condition_variable cv;
    int retValue;

    std::thread t([&cv, &retValue]() 
    {
        retValue = foo();
        cv.notify_one();
    });

    t.detach();

    {
        std::unique_lock<std::mutex> lock(m);
        if(cv.wait_for(lock, 60s) == std::cv_status::timeout) 
            throw std::runtime_error("Timeout");
    }

    return retValue;    
}

int main()
{
    bool timedout = false;
    try {
        foo_wrapper();
    }
    catch(std::runtime_error& e) {
        std::cout << e.what() << std::endl;
        timedout = true;
    }

    if(!timedout)
        std::cout << "Success" << std::endl;
    else
        std::cout << "Failure" << std::endl;

    return 0;
}

If we use std::this_thread::sleep_for(10s); inside foo will return SUCCESS And, if we use std::this_thread::sleep_for(70s); inside foo will return TIMEOUT

I hope it helps!