The following code:
template <typename S, typename T> struct foo { void bar(); }; template <typename T> void foo <int, T>::bar() { }
gives me the error
invalid use of incomplete type 'struct foo<int, T>' declaration of 'struct foo<int, T>'
(I'm using gcc.) Is my syntax for partial specialization wrong? Note that if I remove the second argument:
template <typename S> struct foo { void bar(); }; template <> void foo <int>::bar() { }
then it compiles correctly.
You can't partially specialize a function. If you wish to do so on a member function, you must partially specialize the entire template (yes, it's irritating). On a large templated class, to partially specialize a function, you would need a workaround. Perhaps a templated member struct (e.g. template <typename U = T> struct Nested
) would work. Or else you can try deriving from another template that partially specializes (works if you use the this->member
notation, otherwise you will encounter compiler errors).
Although coppro mentioned two solutions already and Anonymous explained the second one, it took me quite some time to understand the first one. Maybe the following code is helpful for someone stumbling across this site, which still ranks high in google, like me. The example (passing a vector/array/single element of numericalT as dataT and then accessing it via [] or directly) is of course somewhat contrived, but should illustrate how you actually can come very close to partially specializing a member function by wrapping it in a partially specialized class.
/* The following circumvents the impossible partial specialization of a member function actualClass<dataT,numericalT,1>::access as well as the non-nonsensical full specialisation of the possibly very big actualClass. */ //helper: template <typename dataT, typename numericalT, unsigned int dataDim> class specialised{ public: numericalT& access(dataT& x, const unsigned int index){return x[index];} }; //partial specialisation: template <typename dataT, typename numericalT> class specialised<dataT,numericalT,1>{ public: numericalT& access(dataT& x, const unsigned int index){return x;} }; //your actual class: template <typename dataT, typename numericalT, unsigned int dataDim> class actualClass{ private: dataT x; specialised<dataT,numericalT,dataDim> accessor; public: //... for(int i=0;i<dataDim;++i) ...accessor.access(x,i) ... };
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