Integer.parseInt number format exception?

Question

I feel like I must be missing something simple, but I am getting a NumberFormatException on the following code:

System.out.println(Integer.parseInt("howareyou",35)) 

Ideone

It can convert the String yellow from base 35, I don't understand why I would get a NumberFormatException on this String.

Answer 1

Because the result will get greater than Integer.MAX_VALUE

Try this

System.out.println(Integer.parseInt("yellow", 35)); System.out.println(Long.parseLong("howareyou", 35)); 

and for

Long.parseLong("abcdefghijklmno",25) 

you need BigInteger

Try this and you will see why

System.out.println(Long.MAX_VALUE); System.out.println(new BigInteger("abcdefghijklmno",25)); 

Answer 2

Could it be that the number is > Integer.MAX_VALUE? If I try your code with Long instead, it works.