Int division: Why is the result of 1/3 == 0?

Question

The two operands (1 and 3) are integers, therefore integer arithmetic (division here) is used. Declaring the result variable as double just causes an implicit conversion to occur after division.

Integer division of course returns the true result of division rounded towards zero. The result of 0.333... is thus rounded down to 0 here. (Note that the processor doesn't actually do any rounding, but you can think of it that way still.)

Also, note that if both operands (numbers) are given as floats; 3.0 and 1.0, or even just the first, then floating-point arithmetic is used, giving you 0.333....

1/3 uses integer division as both sides are integers.

You need at least one of them to be float or double.

If you are entering the values in the source code like your question, you can do 1.0/3 ; the 1.0 is a double.

If you get the values from elsewhere you can use (double) to turn the int into a double.

int x = ...;
int y = ...;
double value = ((double) x) / y;

Explicitly cast it as a double

double g = 1.0/3.0

This happens because Java uses the integer division operation for 1 and 3 since you entered them as integer constants.

you should use

double g=1.0/3;

or

double g=1/3.0;

Integer division returns integer.